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4 years ago

Rewrite the following statement using a number in scientific notation.

Mathematics

1 answer:

expeople1 [14]4 years ago

6 0

360 000 000 000

Count backwards for the last zero to between the 3 and 6. You should get 11 places.

3.6 * 10^11 <<<< Answer

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The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (x) after x years is given by:

$f(x) = 0.69\cdot(1.03)^{x}$

After x = 0 years, the price of product A is:

$f(0) = 0.69\cdot(1.03)^{0}=0.69$

After x = 1 years, the price of product A is:

$f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)$

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after x = 2 years, the price of product A is:

$f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)$

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t) Price [f (t)]

1 10,100

2 10,201

3 10,303.01

4 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%$

Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%$

Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

$\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%$

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0

3 years ago

Eleven subtracted from the quotient of a number and five is -13

madam [21]

X/5 - 11 = -13

x/5 - 11 (+11) = -13 (+11)

x/5 = -2

x/5 (5) = -2(5)

x = -10

-10 is your number

hope this helps

5 0

3 years ago

Which equations represent inverse variation? Check all that apply.

Bogdan [553]

For this case, what you should know is that the equations that represent an inverse variation are those that could not form a straight line, for example.

We have then:
Equation 1:
pv = 13
Rewriting:
p = 13 / v
P and v are represent an inverse variation.
Equation 2:
z = (2 / x)
z and x are represent an inverse variation.
Answer:
equations represented inverse variation are:
pv = 13
z = (2 / x)

4 0

3 years ago

Read 2 more answers

What is the percent of change from 14 inches 26 inches

PolarNik [594]

To find the percent of anything, you divide what you have from the total (or the smaller number over the bigger number). In this case, you will do 14/26.
14/26=0.53846
I'm going to round to the hundredths: 0.54
Move the decimal place two times to the right: 54
The percent change from 14 inches to 26 inches is 54%

4 0

3 years ago

Hours worked 6 Hourly wage 3.95 Plus tips 21.65

AleksandrR [38]

The answer is $45.35

4 0

3 years ago