There are bills of one dollar, five dollars and ten dollars on the cash drawer, therefore the sum of all of them multiplied by their respective values must be equal to the total amount of money on the drawer. We will call the number of one dollar bills, five dollar bills and ten dollar bills, respectively "x","y" and "z", therefore we can create the following expression:

$x + 5*y + 10*z = 227$

We know that there are six more 5 dollar bills than 10 dollar bills and that the number of 1 dollar bills is two more than 24 times the number of 10 dollar bills, therefore:

$y = z + 6\\x = 2 + 24*z$

Applying these values on the first equation, we have:

$2 + 24*z + 5*(z + 6) + 10*z = 227\\2 + 24*z + 5*z + 30 + 10*z = 227\\39*z + 32 = 227\\39*z = 227 - 32\\39*z = 195\\z = \frac{195}{39}\\z = 5$

Applying z to the formulas of y and x, we have:

$y = 5 + 6 = 11\\x = 2 + 24*5 = 122$

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

4 0

3 years ago

You are saving money for a new phone. You must have at least $800 saved up in

NeX [460]

Let number of hours needed to work = x

Multiply number of hours by rate: 15x

Add what you already have saved:

15x + 215

This needs to equal at least 800:

The equation becomes:

15x + 215 >= 800

Solve for x:

15x + 215 >= 800

Subtract 215 from both sides

15x >= 585

Divide both sides by 15

X >= 39

They have to work at least 39 hours.

6 0

3 years ago

What is x/-3+20=30? Can someone pls help me

VARVARA [1.3K]

Answer:

x=510

Step-by-step explanation:

You can first combine like terms to get x/17=30

The inverse operation of division is multiplication so you can multiply by 17 on both sides to get your final answer: x=510

5 0

2 years ago