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3 years ago

What is the interquartile range of the data? With the numbers 2,3,3,4,5,7,8,8,8,10,10, and 12

Mathematics

1 answer:

harina [27]3 years ago

6 0

Answer:

The interquartile range = 5.5

Step-by-step explanation:

Given the data

2 3 3 4 5 7 8 8 8 10 10 12

As we know that

The interquartile range is the difference between the third and first quartiles.

The first quartile is the median of the bottom half of the numbers.

So, to find the first quartile, we need to place the numbers in value order and find the bottom half.

2 3 3 4 5 7 8 8 8 10 10 12

So, the bottom half is

2 3 3 4 5 7

The median of these numbers is 3.5.

The third quartile is the median of the upper half of the numbers.

So, to find the third quartile, we need to place the numbers in value order and find the upper half.

2 3 3 4 5 7 8 8 8 10 10 12

So, the upper half is

8 8 8 10 10 12

The median of these numbers is 9

The third quartile is 9.

The first quartile is 3.5.

The interquartile range is the difference between the third and first quartiles.

The interquartile range = 9 - 3.5 = 5.5

Therefore, the interquartile range = 5.5

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TiliK225 [7]

GIVEN

The following values are given:

$\begin{gathered} \mu=10.3 \\ \sigma=3.8 \end{gathered}$

SOLUTION

The z-score for the x values 9 and 14 can be calculated using the formula:

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For x = 9:

$\begin{gathered} z=\frac{9-10.3}{3.8} \\ z=-0.34 \end{gathered}$

For x = 14:

$\begin{gathered} z=\frac{14-10.3}{3.8} \\ z=0.97 \end{gathered}$

The probability can be calculated as follows:

$P(9\le x\le14)=Pr(-0.34The region that represents the solution is shown below:Therefore, the probability is given to be:[tex]P(9\le x\le14)=0.4671$

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4 years ago

Event v occurs 28% of the time on Tuesdays.

vampirchik [111]

Answer:

68%

Step-by-step explanation:

Probability of occurrence of Event v = P(v) = 28% = 0.28

Probability of occurrence of both Events v and Event w together = P(v and w) = 19% = 0.19

We have to find what is the probability that event w occurs with event v given that event v occurs on a Tuesday. This is a conditional probability. In other words we have to find what is the probability of event w given that event v occurs of Tuesday. i.e we have to find P(w|v)

The formula to calculate this conditional probability is:

$P(w|v) = \frac{P(v \cap w)}{P(v)}$

Using the given values, we get:

$P(w|v) = \frac{0.19}{0.28}\\\\ P(w|v) = 0.68\\\\ P(w|v) = 68\%$

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Find the vertical asymptote for y=x^2-5x/x^2-x-2

grigory [225]

Answer:

vertical asymptote at x=2 and x=-1

Step-by-step explanation:

$y= \frac{x^2-5x}{x^2-x-2}$

To find out vertical asymptote we set the denominator =0 and solve for x

$x^2 - x - 2=0$

now factor left hand side

find out two factors whose product is -2 and sum is -1

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