I assume you want to know a permutation about how many ways they can be in the final set-up.
Order matters, which is why this is a permutation.
Formula: P(n, r) =

where the permutation is

, with P for permutation.
Plug in:
4!/(4-2)!
4!/2!
(1 x 2 x 3 x 4)/1 x 2
(3x4)/1
= 12
12 ways.
Answer:
Step-by-step explanation:
Enter values of which highlighted variable?
Answer:
1. 6 exponent 3+4
2.6+4 exponent 3
3.6 exponent 3 - 4 exponent 3
Answer:
3.1 3.25 3.33 3.4
Step-by-step explanation: