Let the first term, common difference and number of terms of an AP are a, d and n respectively.
Given that, 9th term of an AP, T9 = 0 [∵ nth term of an AP, Tn = a + (n-1)d]
⇒ a + (9-1)d = 0
⇒ a + 8d = 0 ⇒ a = -8d ...(i)
Now, its 19th term , T19 = a + (19-1)d
= - 8d + 18d [from Eq.(i)]
= 10d ...(ii)
and its 29th term, T29 = a+(29-1)d
= -8d + 28d [from Eq.(i)]
= 20d = 2 × T19
Hence, its 29th term is twice its 19th term
Algebra I believe but I suck at math so don't take my word for it
The value of x that makes lines a and b parallel is 76°.
This is because when two parallel lines are cut by a
transversal, the alternate angles formed by the transversal are equal. In the
figure below, the angle x is an alternative interior angle to the angle
measured 76°, so they are equal. That is, x = 76° (provided that line a is parallel to line b)
Answer:
Your answer
420 were chocolate
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Step-by-step explanation:
