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Nostrana [21]
2 years ago
13

Translating Algebraic Expressions 12 times a x plus 4?

Mathematics
2 answers:
AlexFokin [52]2 years ago
5 0

Answer:

12x+4=0

Step-by-step explanation:

just translate what is written and don't forget to write (=0)

Semmy [17]2 years ago
4 0
12x +4=0

If you are finding x
12x =-4
x=-4/12
x=-1/3
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Write the expression as a product of two factors: 6m + 8n + 4
Ad libitum [116K]

Answer:

1+1=2

Step-by-step explanation:

8 0
3 years ago
The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot
katovenus [111]

Answer:

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

4) The data for shelter B are a symmetric data set.

True, the median is exactly 2 pounds away from each quartile which means it is symmetric.

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

Step-by-step explanation:

We are given two box-plots, a box plot basically shows 5 statistical characteristics of a data set and they are  

1. minimum value  

2. Lower quartile  

3. Median value  

4. Upper quartile  

5. Maximum value  

Box-plot of dogs in shelter A:

The whiskers range from 8 to 30

Which means that the range is = 30 - 8 = 22

The box ranges from 17 to 28

Which means that the interquartile range is = 28 - 17 = 11

21 - 17 = 4

28 - 21 = 9

The median is not equal distance away from each quartile which means that the box-plot is not symmetric.

A line divides the box at 21

Which means that the median is = 21

Box-plot of dogs in shelter B:

The whiskers range from 10 to 28

Which means that the range is = 28 - 10 = 20

The box ranges from 16 to 20

Which means that the interquartile range is = 20 - 16 = 4

18 - 16 = 2

20 - 18 = 2

The median is exactly 2 pounds away from each quartile which means it is symmetric.

A line divides the box at 18

Which means that the median is = 18

Which is true of the data in the box plots?

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

2) The median weight for shelter B is greater than that for shelter A.

False

3) The data for shelter A are a symmetric data set.

False

4) The data for shelter B are a symmetric data set.

True

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

5 0
4 years ago
Lines can be used to approximate a wide variety of functions; often a function can be described using many lines. If a stock pri
4vir4ik [10]

We are given: Price of stock on 1st January = $10.

And price of stock on 31st january = $12.

Let us represent Day number and Price by coordinate (x,y).

Therefore, coordinates for January month can be written as (1,10) and (31,12).

Price of stock on 1st February = $10.

And price of stock on 28th February = $9.

Let us represent Day number and Price by coordinate (x,y).

Therefore, coordinates for February month can be written as (1,12) and (28,9).

Now, we can plot those two different pairs of coordinates for January and February on the graph.

From the graph, we can see that slope of red line is greater and it is positive and slope of green line is negative(because price decreasing).

Therefore, the price change from $10 to $9 is not a straight line.

Therefore, we can say from January 1 to January 31 the rate is inceasing so the slope is positive then after 1 February the rate started decreasing so the slope became negative.

5 0
4 years ago
Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 ​ )left parenthesis, 0, comma
steposvetlana [31]

Answer:

\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

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4 years ago
What is the monomial if a square of a monomial is 1/4a^2n
Burka [1]

Answer:

Answer:

Answer:

1/2a^n

Step-by-step explanation:

Square of the monomial is  

To get the monomial we take square root

Lets take square root for each term

because square root of 4 is 2

2/2 is 1 so, its a^n

Required monomial is  

1/2a^n

Step-by-step explanation:

7 0
3 years ago
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