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3 years ago

Which set of values could be from a direct proportion?

Mathematics

1 answer:

vampirchik [111]3 years ago

7 0

Answer:

The value of k remains constant for table 2

Step-by-step explanation:

Given tables of X values and Y values

To find which tables show the property of direct proportional:

Since Y is direct proportion to X

We write,

y=kx [Equation]

where k is constant of proportion.

Therefore, If the value of k remains constant for any table then, that table shows a direct proportion between y and x values.

For first table :

Now,

when x=1, y=3

Putting into Equation

y=kx

3=k(1)

k=3

Similarly, other calculations are carried out and put it into the form of a table

Note: Figure show tables of given and their respective k values.

Thus, the value of k remains constant for table 2

You might be interested in

F(x) = two divided by quantity x squared minus two x minus three

VARVARA [1.3K]

F(x) = 2÷(x² - 2x - 3)

1)
Domain:
The domain is all the values for x that will produce a real number for y
Factor the denominator to find where y is not defined:
f(x) = 2÷(x² - 2x - 3)
f(x) = 2 ÷ (x-3)(x+1)
The domain is all real numbers except x=3 and x=-1

Range:
The range for y is all the values that y can take, given the domain.
The range is all real numbers, because y approaches both positive and negative infinite at different points on the graph.

The y-intercept is where x=0
y= 2 ÷ (0² - 2(0) -3)
y= 2 ÷ -3 = -2/3

The x-intercept are the points at which y=0.
Let's use the factored form again:
f(x) = 2 ÷ (x-3)(x+1)
This function has no x-intercepts. All values of X either produce a real number, or are undefined in the case of x=3 and x=-1

Horizontal Asymptotes
As X approaches inifinite, how does y behave?
f(x) = 2÷(x² - 2x - 3)
As x approaches both positive and negative infinite, the dominate term in the denominator, x², is vastly greater than 2, and thus y approaches zero.
The horizontal asymptote is zero, in both the positive and negative direction.

Again, let's consult the factored form:
2 ÷ (x-3)(x+1)
There are vertical asymptotes at both x=3 and x=-1. As x approaches these numbers, depending on whether x is a little bigger or smaller than either one, y approaches positive and negative infinite, since the denominator of the function approaches zero.
Therefore, there are both positive and negative vertical asymptotes at both x=3 and x=-1

As for the graph, we'll leave that to you and the many applications that can aid in such a task!

4 0

4 years ago

50 point to the person that can answer this:

ale4655 [162]

Answer:

B. The constant in the expression is 1/2

Step-by-step explanation:

Given formula for the area of a triangle

A = 1/2bh

Statements to confirm

A. The coefficient of is b.

False. b is variable, 1/2 is coefficient

B. The constant in the expression is 1/2

True

C. There is one term in the expression.

False. There are 3 terms, one constant and two variables

D. There is one variable in the expression.

False. There are two variables, b and h

Note.

Assumed 1/2 is given in Option B, otherwise all statements are false.

7 0

3 years ago

Select the statement that best justifies the conclusion based on the given information. B is between A and C Conclusion: A, B an

ivanzaharov [21]

It is c is the collinear

5 0

3 years ago

Read 2 more answers

The frog population at a lake doubles every week. The population can be modeled by f(x) = 15(2)x and f(6) = 960. What does the 9

insens350 [35]

Answer:

a is the correct option.

Step-by-step explanation:

We have been given the population model is $f(x)=15(2)^x, f(6)=960$

Here x represents number of weeks and f(x) is population of frog after x weeks.

For x= 6, we have

$f(6)=15(2)^6\\\\f(6)=15\times 64\\f(6)=960$

It means that the population after 6 weeks is 960.

Hence, f(6)=960 represents the population after 6 weeks.

a is the correct option.

6 0

4 years ago

Given m ||n, find the value of x 167°

frutty [35]

Answer:

Step-by-step explanation:

180-167= 13

× = 13 degrees

7 0

3 years ago