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givi [52]
3 years ago
14

Is the following relation a function? X Y 6 -1 -1 2 4 3 0 3

Mathematics
2 answers:
german3 years ago
5 0
Answer: Given relation is a function

A relation is said to be a function if no value in its domain is paired up with more than one value in its range.

Since x values represent the Domain of a relation and y values represent the Range of a relation, in terms of x and y we can say:

A relation is said to be a function if an x-value is not paired up with more than one y-value.

From the above table we can see that all the x values are distinct, so no x value is paired with more than one y-value and thus given relation is a function. 
PIT_PIT [208]3 years ago
4 0
Note that the input values {6, -1, 4, 0} are unique (all different).  So, yes, this relation is a function.  If the input values were  {6, -1, 4, -1, 0}, then no, that would not represent a function because the input values were not unique.

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Read 2 more answers
5x+20y=4<br> x=-4y+1<br><br> Solve for x/y
Andrews [41]

Hi there!


Looks like a lot of work is going on here.


Let's start by solving this equation for the x.


5x + 20y = 4


Step 1) Add -20y to both sides.


5x + 20y + - 20y = 4 - 20y 5x = -20y + 4


Step 2) Divide both sides by 5.


\frac{5x}{5}  = \frac{-20y + 4}{5}


x = -4y +  \frac{4}{5}


Final Answer:


x = -4y +  \frac{4}{5}


Now, let's solve for y.


Step 1) Add -5x to both sides.


5x + 20y + - 5x = 4 + - 5x 20y = -5x + 4


Step 2) Divide both sides by 20.


\frac{20y}{20} =  \frac{-5x + 4}{20}


y =  \frac{-1}{4} x +  \frac{1}{5}


Final Answer:


y =  \frac{-1}{4} x +  \frac{1}{5}


Hope this helps! :D


Hint - When you have two variables in an equation, and you want to solve for one, the other will end up in your answer. :)

6 0
4 years ago
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