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3 years ago

Grant is rolling a standard six-sided number die 8 times. How many outcomes are possible

1 answer:

3 0

I’m not a 100% sure but if there six sides and u roll it eight times you can do 6 x 8 = 48, so your answer is 48 (I think)

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-5=0.1x-8.5 what is the answer

astra-53 [7]

Answer:

x = 35

Step-by-step explanation:

hope this helps

4 0

2 years ago

Read 2 more answers

Help with geometry please! I don't know how to do this

sesenic [268]

We know that
scale factor=2.5
volume larger warehouse=scale factor³*volume smaller warehouse
volume larger warehouse=2.5³*volume smaller warehouse
volume larger warehouse=[15.625]*volume smaller warehouse

that means
the volume of the larger warehouse is 15.625 times the volume smaller warehouse

the energy and cost is proportional to the volume
so
the new cost is 15.625*$125-----> $1953.12------> $1953

the answer is
$1953

4 0

3 years ago

A)3<br> B)2 <br> C)15<br> D)-3<br> I Need The Answer Plz Geometry is Tuff

Cerrena [4.2K]

I’m pretty sure Y is 15

7 0

3 years ago

Simplify the following expression by combining like terms.

Dima020 [189]

Answer: The answer should be 16x^2-4x

5 0

3 years ago

Jackie scored 81 and 87 on her first two quizzes . Write and solve a compound inequality to find the possible values for a third

asambeis [7]

Answer:

The third score must be larger than or equal to 72, and smaller than or equal 87

Step-by-step explanation:

Let's name "x" the third quiz score for which we need to find the values to get the desired average.

Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

$average=\frac{81+87+x}{3}$

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

$80\leq average\leq 85\\80\leq \frac{81+87+x}{3} \leq 85\\80\leq \frac{168+x}{3} \leq 85$

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

$80\leq \frac{168+x}{3}\\3*80\leq 168+x\\240\leq 168+x\\240-168\leq x\\72\leq x$

This inequality tells us that the score in the third quiz must be larger than or equal to 72.

Now we study the second inequality to find the other restriction on "x":

$\frac{168+x}{3} \leq 85\\168+x\leq 85 *3\\168+x\leq 255\\x\leq 255-168\\x\leq 87$

This ine $72\leq x} \leq 87$ quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.

Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:

4 0

3 years ago