Answer:
A Punnett square for the following monohybrid cross can be shown as follows:
s s
S Ss Ss
S Ss Ss
a) The genotype of the potential offspring will be Ss, they will be heterozygous dominant.
b) There is a zero% probability that the offspring will have no freckles. As one of the parents was homozygous dominant for the freckles, hence all of the offsprings will have freckles.
Answer:
transform boundary: when two plates slide past each other
divergent boundary: when two plates pull away from each other
convergent boundary: when two plates collide with each other
:)
Answer:
<em>The child with the blood type O will be adopted. </em>
Explanation:
A punnet square can be described as a diagram which is made to depict the outcomes of a cross.
To determine the possible blood groups of the children with parents having AB and O blood group, lets make a punnet square:
O O
A AO AO
B BO BO
The punnet square shows that the children produced will have 50 percent chance of having A blood group and a 50 percent chance of having a B blood group. Hence, we can tell that the child with O blood group is adopted.
The expression which is the correct way to calculate the frequency of the dominant allele is 134/200. Thus, the correct option is D.
<h3>What is Allelic frequency?</h3>
The allelic frequency may be defined as the sum total of all the alleles of a gene in a population. It represents the overall genetic diversity within a population.
The allelic frequency is calculated by the formula when the genotypes are given in number. It is as follows:
2 × Number of Purebred dominant + Number of heterozygous/ 2× Total number of individuals in a population.
∴ Allelic frequency of dominant allele = 2 × 50 + 34/ 2× 100 = 134/200 = 0.67.
The allelic frequency of the Dominant allele is 0.67 while the allelic frequency of the recessive allele is 0.33.
Therefore, it is well described above.
To learn more about Allelic frequency, refer to the link:
brainly.com/question/14649601
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