Answer:
- 6(x^2 +18z +81) . . . as written
- 6(x +9)^2 . . . . . . . . assuming a typo
Step-by-step explanation:
As the expression is written, the only factoring that can be done is to factor out the common numeric factor of 6:
= 6(x^2 +18z +81)
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<em>Assuming a typo in the question</em>
If we assume all variables are supposed to be "x", then the quadratic term can be further factored as a square:
= 6(x +9)^2
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It is often handy to remember that the form of the square of a binomial is ...
(a +b)^2 = a^2 +2ab +b^2
Here, we recognize that 18 = 2√81, so the binomial is (x +√81) = (x +9).
To write a fraction in simplest form, you have to divide the numerator and the denominator by their greatest common factor.
Factors of 10: 1, 2, 5, 10
Factors of 64: 1, 2, 4, 8, 16, 32, 64
Common Factors: 1, 2
Greatest Common Factor: 2
(x+1)(2x+3)
Hope this helps you
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
