Question

a cup was filled at a constant rate. it started empty. after 2 seconds, it held 70 cm cubes of water. the radius is 4 and te height is 7. find the percent of the cup that is filled with water after 3 seconds. this is a cone

Answer 1

Answer:

89.51%

Step-by-step explanation:

Assuming given units are in cm

Tge rate of filling the cup is 70/2= 35 cm3/s

Volume of the cup is $\pi r^{2}\frac {h}{3}$ and replacing r with 4 cm and h with 7 cm then the volume is equivalent to

$\pi*4^{2}*\frac {7}{3}= 117.3 cm^{3}$

Volume filled after 3 seconds will be 3*35=105 cm3

Percentage filled is $\frac {105}{117.3}\times 100\approx 89.51$