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borishaifa [10]
3 years ago
10

Write a rational function whose graph has a vertical asymptote of x = 6

Mathematics
2 answers:
tekilochka [14]3 years ago
7 0

Answer:

y=1x(x−6)

Step-by-step explanation:

I hope this helps answer your question(s). Please mark brainliest.

pishuonlain [190]3 years ago
4 0
<h2>>> Answer </h2>

_______

\:

  • Step by step :

x = 6

Soo graph in the picture!

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GIVE U BRAINLYIST IF U GET CORRECT ANSWER AND EXTRA POINTS
kherson [118]

Answer:

Point N

Step-by-step explanation:

6 0
3 years ago
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I need help with this
alexira [117]

Answer:

g(x)=log(x+4)

Step-by-step explanation:

Here the parent function is f(x)=log x. The function has y intercept as 0 at x=1 .

If we observe the translated function we will observe that , the y intercept of new function is 0 at x=-3. Hence the function is moving ahead of the parent function by 4 units and reaches the y intercept being 0.

If we graph

g(X)= log X

the y intercept will be at (1,0)

X = 1 , Y =0

at X=1 , x = -3  or x = X-4

or X=x+4

Hence

new function will be g(x)=log ( x+4)

8 0
3 years ago
Please help! Picture attached. (7th grade)
Hunter-Best [27]
Option B. 2 because 2-8
                                 ------- = -3
                                     2
8 0
3 years ago
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A thermometer is taken from a room where the temperature is 24oc to the outdoors, where the temperature is −15oc. After one minu
kap26 [50]

Solution:

Use Newton's Law of Cooling.  


T = T_s + (T_0 - T_s)*e^(-kt)  


where  

T = temperature at any instant  

T_s = temperature of surroundings  

T_0 = original temperature  

t = elapsed time  

k = constant  


Now, we need to find this constant. We are given that after one hour, the temperature drops to 13° C in a 7°C Environment.  

T = 14, T_0 = 24, T_s = -15, t = 1, k = ?  

T = T_s + (T_0 - T_s)*e^(-kt)  

==> 14 = -15 + (24 - 7)*e^(-k)  

==> 14 = 7 + 17*e^(-k)  

==> 7 = 17*e^(-k)  

==> 7/13 = e^(-k)  

==> -k = ln(7/17)  

==> k = -ln(7/17) ≈ 0.774  

Now,


Let's calculate temperatures!  

T = ?, T_0 = 24, T_s = -15, k = 0.773, t = 3  

T = T_s + (T_0 - T_s)*e^(-kt)  

==> T = -15 + (24 –(-15))*e^[ -(0.774)(2) ]  

==> T = -15 + 39*e^(-1.548)  

==> T ≈ 15.72° C  

This the required answer.


7 0
3 years ago
Combine the like terms to make a similar expression 2q+2+9
Ede4ka [16]
Add the 2 and 9 together:
2q+11
8 0
3 years ago
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