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labwork [276]
3 years ago
6

For the differential equation s′′+bs′+6s=0, find all the values of b that make the general solution overdamped, those that make

it underdamped, and those that make it critically damped. (For each, give an interval or intervals for b for which the equation is as indicated. Thus if the the equation is overdamped for all b in the range 2

Mathematics
1 answer:
djyliett [7]3 years ago
6 0

Answer:

<em><u>note:</u></em>

<em><u>solution is attached</u></em>

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Please help me with this​
aliya0001 [1]

Answer and Step-by-step explanation:

1/2x is positive and 2 is negative, so they cross each other perpendicularly, and the equation needs to be at -13 y, 0 x

The answer is y = -2x - 13

#teamtrees #WAP (Water And Plant)

7 0
2 years ago
Select the correct answer from each drop-down menu.
Annette [7]

All of given options contain quadratic functions. One way to determine the extreme value is squaring the expression with variable x.

Option B contain the expression where you can see perfect square. Thus, equation \bf{y=-(x-2)^2+5} (choice B) reveals its extreme value without needing to be altered.

To determine the extreme value of this equation, you should substitute x=2 (x-value that makes expression in brackets equal to zero) into the function notation:

y=-(2-2)^2+5=5.

The extreme value of this equation has a minimum at the point (2,5).

7 0
2 years ago
Read 2 more answers
Determine the intercepts of the line.<br> y=5x-13<br><br> Y-Intercept ( , )<br> X-Intercept ( , )
Arte-miy333 [17]

Answer:

Y-intercept is (0, -13)

X-intercept is at (13/5, 0)

Step-by-step explanation:

When it's in this form, y = mx + b, you automatically know what the y-intercept is (b).

So the y-intercept is (0, -13)

To algebraically find this, you'd plug in a 0 for x, since the y intercept is when it crosses the y-axis, which is located at x = 0.

To find the x intercept, you'd do the opposite of the y-intercept, which is plugging in a 0 for y and solving for x. The x-axis is located at y = 0.

0 = 5x - 13

13 = 5x

x = 13/5

The x-intercept is at (13/5, 0)

I hope this helped!

3 0
3 years ago
Help please! (no one was answering it in physics and i really need help)
aivan3 [116]

Let v_0 be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time t is given by

x(t)=v_0t

and its height is

y(t)=1.3\,\mathrm m-gt^2

where g is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is t with

0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed v_0 was

0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0
3 years ago
Round 48.47 to the ones place
WINSTONCH [101]

Answer:

48.7 I think

Step-by-step explanation:

hears the sender buddy

5 0
2 years ago
Read 2 more answers
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