1331 x³ = 216
x³ = 216/1331
x =![\sqrt[3]{ \frac{216}{1331} } = \frac{6}{11}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B216%7D%7B1331%7D%20%7D%20%3D%20%20%5Cfrac%7B6%7D%7B11%7D%20)
Thank you.
x³ = 216/1331
x =
Thank you.
For the differential equation s′′+bs′+6s=0, find all the values of b that make the general solution overdamped, those that make
it underdamped, and those that make it critically damped. (For each, give an interval or intervals for b for which the equation is as indicated. Thus if the the equation is overdamped for all b in the range 2
1 answer:
You might be interested in
Slope-intercept form:
y = mx + b
"m" is the slope, "b" is the y-intercept
To find "m", you can use the slope formula and plug in the two points:
The slope is 0 so:
y = mx + b
y = 0x + b [any number multiplied by 0 is 0]
y = b
To find "b", you plug in either of the points into the equation (since both of their y values are 1]
y = b
1 = b
Your equation is:
y = 1 (This is a horizontal line)