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Mumz [18]
3 years ago
11

What’s -7 1/3 divided by 1 2/9

Mathematics
1 answer:
Degger [83]3 years ago
8 0

-7 13÷ by 1 2/9 equals. -11 1/2

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Determine the number of terms, n, given the geometric series 1 3 9 27 ... and sn=3280.
lina2011 [118]

The number of terms, 'n' is 8

<h3 /><h3>How to determine the number of terms</h3>

Let's determine the common ratio;

common ratio, r = 3/1 = 3

The formula for sum of geometric series with 'r' greater than 1 is given as;  Sn = a( r^n - 1) / (r - 1)

n is unknown

Sn = 3280

Substitute the value

3280 = 1 ( 3^n - 1) / 3- 1

3280 = 3^n -1 /2

Cross multiply

3280 × 2 = 3^n - 1

6560 + 1 = 3^n

6561 = 3^n

This could be represented as;

3^8 = 3^n

like coefficient cancels out

n = 8

Thus, the number of terms, 'n' is 8

Learn more about geometric series here:

brainly.com/question/24643676

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5 0
1 year ago
a swimmer swam 48 kilometers in d days. What is the value of the d if the swimmer swam an average of 3.2 kilometers daily?
lianna [129]
Time= distance/speed

=48/3.2= 15
6 0
3 years ago
How do I solve this?​
crimeas [40]

Answer:

The final answer is (2,-1)

(also idek what I did in the photo but I'm positive the answer is (2,-1)

7 0
2 years ago
-13 =\dfrac r9+8−13= <br> 9<br> r<br> ​ <br> +8
inna [77]

Answer:

Ello, estoy aquí para ayudar, pero hablo español, con suerte, entenderás que lo estoy intentando.

56738w7421098548091672949123749279102

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
let p be the number of primes less than 100, and let Q be the number of primes less than 90. What is the value of P-Q?
3241004551 [841]

The value of P - Q as described in the question above is; P -Q = 2.

According to the question;

  • P = number of primes less than 100
  • Q = number of primes less than 90

Since, we are required to determine what the value of P-Q is;

The value of P-Q is simply the number of primes between 90 and 100.

The prime numbers between 90 and 100 are; 91 and 97.

Therefore, P - Q = 2.

Read more;

brainly.com/question/22257959

3 0
2 years ago
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