Answer:
x=19
Step-by-step explanation:
5(x+35)=9(300
5x+175=270
5x=270-175
5x=95
95/5=19X
The largest number that 8c could be is -15
75x+35≥7(11x+9)+475x+35≥7(11x+9)+4
75x+35≥77x+63+475x+35≥77x+63+4 [expand all blackets]
75x+35≥77x+6775x+35≥77x+67 [collect like terms]
−2x+35≥67−2x+35≥67 −2x≥32−2x≥32 [subtract 77x through]
x≤−16x≤−16 [subtract 35 through and divide through by 2]
Answer:
17.5ml- of 10 percent solution, 17.5ml- of 20 percent solution
Step-by-step explanation:
35:100*15=5.25- ml of alkali in the base solution
Suppose we need x ml of 10 percents solution and 35-x - of 20 percents.
Then The quantity of alkali in the first one (10 percents) is x/100*10=0.1x
when in the second one we have (35-x)/100*20= 7-0.2x of alkali
0.1x+7-0.2x=5.25
7-0.1x= 5.25
0.1x=1.75
x=17.5- 0f 10 percents
35-17.5=17.5 - of 20 percents
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