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Ymorist [56]
3 years ago
12

0.14 repeating decimals

Mathematics
1 answer:
Burka [1]3 years ago
6 0
You would put a line above the .14 and that would Indicate that it’s repeating
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Solve for the measure of a
Lena [83]

Answer:

Step-by-step explanation:

The supplement of the exterior angle is 180 - 75 = 105

In a cyclic quadrilateral (a four sides figure where all the vertices touch the circumference of a circle), the opposite angles are supplementary. Therefore <a = 180 - 105 = 75

But I think you already knew that.

4 0
3 years ago
What is the sign of A +B?
lesya [120]

Answer:

The answer is AB

Step-by-step explanation:

As A+B=AB

6 0
3 years ago
How to do question 1?Had no idea how to do both parts
givi [52]
y=\dfrac{\ln x}{3x-6}

Differentiate both sides with respect to x:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}

When x=1, you have

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}=\dfrac{-3}9=-\dfrac13

For part (b), we now assume that x and y are functions of an independent variable, which we'll call t (for time). Now differentiating both sides with respect to t, we have

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}\dfrac{\mathrm dx}{\mathrm dt}

where the chain rule is used on the right side. We're told that y is decreasing at a constant rate of 0.1 units/second, which translates to \dfrac{\mathrm dy}{\mathrm dt}=-0.1. So when x=1, you have

-0.1=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}\dfrac{\mathrm dx}{\mathrm dt}
-0.1=-\dfrac13\dfrac{\mathrm dx}{\mathrm dt}
\dfrac{\mathrm dx}{\mathrm dt}=0.3

where the unit is again units/second.
6 0
3 years ago
-14x &gt; -3 can someone help please
I am Lyosha [343]

Answer:

.

Step-by-step explanation:

8 0
3 years ago
Plz help! ASAP! What is the expression shown below
astra-53 [7]

we are given

\frac{1}{2} (\frac{3}{2} x+6x+1)-3x

step-1: Simplify expression inside parenthesis

we will combine like terms

so, firstly we will take common denominator

\frac{1}{2} (\frac{3}{2} x+\frac{2*6}{1*2}x+1)-3x

\frac{1}{2} (\frac{3x+12x}{2} +1)-3x

\frac{1}{2} (\frac{15x}{2} +1)-3x

step-2: Distribute 1/2 inside

=\frac{1}{2} *\frac{15x}{2} +1*\frac{1}{2}-3x

=\frac{15x}{4} +\frac{1}{2} -3x

step-3: Combine like terms

=\frac{15x}{4}+3x +\frac{1}{2}

We can find common denominator

=\frac{15x}{4}-\frac{4*3x}{4*1} +\frac{1}{2}

=\frac{15x}{4}-\frac{12x}{4} +\frac{1}{2}

=\frac{15x-12x}{4} +\frac{1}{2}

=\frac{3x}{4} +\frac{1}{2}

we can also write it as in mixed form

=\frac{3}{4}x +\frac{1}{2}

so, we will get

\frac{1}{2} (\frac{3}{2} x+6x+1)-3x=\frac{3}{4}x +\frac{1}{2}

option-C.............Answer

5 0
4 years ago
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