0.14 repeating decimals

AB 1 CD. Find x.<br> 4x + 50

yKpoI14uk [10]

Answer:

4x +50=90

X=(90-50):4

X=10

8 0

2 years ago

Compare the line passing through the points (–2, –9) and (4, 6) to the line given by the equation y = 25x – 4.

elena-s [515]

Answer:

D. They have the same y-intercep

Step-by-step explanation:

Before the comparison will be efficient, let's determine the equation of the two points and the x intercept .

(–2, –9) and (4, 6)

Gradient= (6--9)/(4--2)

Gradient= (6+9)/(4+2)

Gradient= 15/6

Gradient= 5/2

Choosing (–2, –9)

The equation of the line

(Y+9)= 5/2(x+2)

2(y+9)= 5(x+2)

2y +18 = 5x +10

2y =5x -8

Y= 5/2x -4

Choosing (4, 6)

The equation of line

(Y-6)= 5/2(x-4)

2(y-6) = 5(x-4)

2y -12 = 5x -20

2y = 5x-8

Y= 5/2x -4

From the above solution it's clear that the only thing the both equation have in common to the given equation is -4 which is the y intercept

4 0

3 years ago

Hii please help i’ll give brainliest if you give a correct answer

tino4ka555 [31]

Answer:

x * 3/8(s) = 5/4

5/4 ÷ 3/8(s) = x

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Answer number 8 please I’m begging u

Andrews [41]

Answer:

Probability - spinner 1

1/5 - not likely

Probability - spinner 2

1/8 - not likely

Step-by-step explanation:

8 0

2 years ago

This is a 3 part 1 question each part on how to locate the plane and a small explanation report working out the recovery details

sesenic [268]

Third leg.

The crew flies at a speed of 560 mi/h in direction N-20°-E.

The wind has a speed of 35 mi/h and a direction S-10°-E.

We then can draw this as:

We have to add the two vectors to find the actual speed and direction.

We will start by adding the x-coordinate (W-E axis):

$\begin{gathered} x=560\cdot\sin (20\degree)+35\cdot\sin (10\degree) \\ x\approx560\cdot0.342+35\cdot0.174 \\ x\approx191.53+6.08 \\ x\approx197.61 \end{gathered}$

and the y-coordinate (S-N axis) is:

$\begin{gathered} y=560\cdot\cos (20\degree)-35\cdot\cos (10\degree) \\ y\approx560\cdot0.940-35\cdot0.985 \\ y\approx526.23-34.47 \\ y\approx491.76 \end{gathered}$

Then, the actual speed vector is v3=(197.61, 491.76).

The starting location for the third leg is R2=(216.66, 167.67) [taken from the previous answer].

Then, we have to calculate the displacement in 20 minutes using the actual speed vector.

We can calculate the movement in each of the axis. For the x-axis:

$\begin{gathered} R_{3x}=R_{2x}+v_{3x}\cdot t \\ R_{3x}=216.66+197.61\cdot\frac{1}{3} \\ R_{3x}=216.66+65.87 \\ R_{3x}=282.53 \end{gathered}$

NOTE: 20 minutes represents 1/3 of an hour.

We can do the same with the y-coordinate:

$\begin{gathered} R_{3y}=R_{2y}+v_{3y}\cdot t \\ R_{3y}=167.67+491.76\cdot\frac{1}{3} \\ R_{3y}=167.67+163.92 \\ R_{3y}=331.59 \end{gathered}$

The final position is R3 = (282.53, 331.59).

To find the distance from the origin and direction, we transform the cartesian coordinates of R3 into polar coordinates:

The distance can be calculated as if it was a right triangle:

$\begin{gathered} d^2=x^2+y^2_{} \\ d^2=282.53^2+331.59^2 \\ d^2=79823.20+109951.93 \\ d^2=189775.13 \\ d=\sqrt[]{189775.13} \\ d\approx435.63 \end{gathered}$

The angle, from E to N, can be calculated as:

$\begin{gathered} \tan (\alpha)=\frac{y}{x} \\ \tan (\alpha)=\frac{331.59}{282.53} \\ \tan (\alpha)\approx1.1736 \\ \alpha=\arctan (1.1736) \\ \alpha=49.56\degree \end{gathered}$

If we want to express it from N to E, we substract the angle from 90°:

$\beta=90\degree-\alpha=90-49.56=40.44\degree$

Answer: the final location can be represented with the vector (282.53, 331.59).

1) The distance from the origin is 435.63 miles and

2) the direction is N-40°-E.

7 0

8 months ago