In triangle ABC,
AC = 12/ (sin30) = 12 / (1/2) = 24
DC = 24-x
DB = DC tan 30 = (24-x) tan30 <span>=(24−x)/</span><span>√3
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In triangle ADB using Pythagorean Theorem<span><span>x2</span>+((24−x)/<span>√3</span><span>)2</span>=<span>12^2</span></span><span><span>x2</span>+(24−x<span>)^2</span>/3=<span>12^2</span></span><span>3<span>x2</span>+(24−x<span>)^2</span>=432</span><span>4<span>x2</span>−48x+576=432</span><span>4<span>x2</span>−48x+144=0</span><span><span><span>x2</span>−12x+36=0
x1 = x2 =6
AD = AC - DC = 24- (24-x) = 6</span></span>
Answer: (3) f(8) = g(8)
<u>Step-by-step explanation:</u>
Let's compare the values of f(x) and g(x) when x = 0, 2, 8, and 4
<u> f(x) </u> <u> g(x) </u> <u>Comparison</u>
f(x) = 2x - 3 
f(0) = 2(0) - 3 
= -3 = 1 f(0) < g(0)
f(2) = 2(2) - 3 
= 1 = 4 f(2) < g(2)
f(8) = 2(8) - 3 
= 13 = 13 f(8) = g(8)
f(4) = 2(4) - 3 
= 5 = 7 f(4) < g(4)
The only statement provided that is true is f(8) = g(8)
it's plural so axes*
and in pilar coordinates, the axes are circular so they never intersect but the centre point is still called origin.
1 yard = 3 feet
F ( y ) = 3 y
F ( 10.5 ) = 3 yard * 10.5 feet / yard = 31.5 feet
Answer:
The output will be 31.5
Answer:
Squares 6*6 and 2*2 are similar to square 3*3
