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2 years ago

Calcula eldivisor de lassiguientescantidades28 y 3036 y 458

Mathematics

1 answer:

Maru [420]2 years ago

3 0

Answer:

Its math

Step-by-step explanation:

Its math

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Plzzzzz help 3 9/10 is the same as the sum of 3 1/3 and half of a number what is the number

kirill [66]

Answer:

9/10 = 1/3 + 1/2x

9/10 - 1/3 = 1/2x

LCM of 10 and 3 is 30

( 27 - 10)/30 = 1/2x

17/30 = 1/2x

17 * 2 = 30x

34=30x

34/30= 30x/30

x = 17/15

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2 years ago

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a grocery store display has 2 boxes of cereal on the top row,3 boxes in the next row,4 boxes in the next row, and so on. How man

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3 years ago

Read 2 more answers

The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amo

Aloiza [94]

Answer:

$a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]$

Step-by-step explanation:

a. -Given that:

$n_m=41\ , \ \sigma_m=33, \bar x_m=135.67\\\\n_f=37. \ \ ,\sigma_f=20, \ \ \bar x_f=68.64$

#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:

$\bar x_m-\bar x_f\\\\\therefore \bigtriangleup\bar x=135.67-68.64\\\\=67.03$

Hence, the pointer is estimator 67.03

b. The standard error of the point estimator, $\bar x_m-\bar x_f$ is calculated by the following following:

$\sigma_{\bar x_m-\bar x_f}=\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

-And the margin of error, E at a 99% confidence can be calculated as:

$E=z_{\alpha/2}\times \sigma_{\bar x_m-\bar x_f}\\\\\\=z_{0.005}\times\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\\\=2.575\times \sqrt{\frac{33^2}{41}+\frac{20^2}{37}}\\\\\\=15.7416$

Hence, the margin of error is 15.7416

c. The estimator confidence interval is calculated using the following formula:

$\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

#We substitute to solve for the confidence interval using the standard deviation and sample size values in a above:

$CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]$

Hence, the 99% confidence interval is [51.2884,82.7716]

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3 years ago

Complete the following statement of congruence:

blagie [28]

Answer:

Step-by-step explanation:

congruence means duplicate so you have to see its reflection

4 0

3 years ago

Calcula eldivisor de lassiguientescantidades28 y 3036 y 458​

Calcula eldivisor de lassiguientescantidades28 y 3036 y 458