How do you solve for x when you have this problem below please explain !!
1 answer:
Answer:
The value of x is 16
Step-by-step explanation:
We can clearly see in the diagram that a transversal is intersecting two parallel lines.
When a transversal intersects two parallel lines, eight angles are formed.
The angles which are in the same position on same side of each line intersected by the transversal, are called corresponding angles.
<u>Corresponding angles are congruent.</u>
So,
Angle 6x+4° and 100° will be congruent or equal
Hence,
The value of x is 16
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Answer:
Step-by-step explanation:
slope intercept form is y = mx + b
b is the y intercept ( crossing y axis value).... by inspection b = -4
m is the slope of the line, Slope = m = 1/4 note: the slope is positive
the slope equals the 'rise' over 'run'
if the line moves up the slope is positive, if the line moves down the slope is negative
the rise is how many y units does the line go 'up' or 'down'
the run is how many x units does the line go 'left' or 'right'
the rise = 1 Y unit
the run = 4 X units
y = mx + b m =1/4 b = -4
y = (1/4)x + (-4)
y = (1/4)x - 4
graph a line stating at y = -4 and going up (rising) to the right ONE Y Unit for every FOUR X units (the run)
Answer:
The graph crosses the x-axis 2 times
The solutions are x = -8 & x = 4
Step-by-step explanation:
Qaudratics are in the form
Where a, b, c are constants
Now, let's arrange this equation in this form:
Where
a = 1
b = 4
c = -32
We need to know the discriminant to know nature of roots. The discriminant is:
If
- D = 0 , we have 2 similar root and there is 2 solutions and that touches the x-axis
- D > 0, we have 2 distinct roots/solutions and both cut the x-axis
- D < 0, we have imaginary roots and it never cuts the x-axis
Let's find value of Discriminant:
Certainly D > 0, so there are 2 distinct roots and cuts the x-axis twice.
We get the roots/solutions by factoring:
Thus,
The graph crosses the x-axis 2 times
The solutions are x = -8 & x = 4