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klemol [59]
3 years ago
10

I NEED HELP QUICKKKKK

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Answer:

the last one

(-15)x12

hope this helps!

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What is the result of dividing x3−4 by x + 2
Snowcat [4.5K]
The answer would be x2 - 2x + 4 - 12/(x + 2) as the final result. Credits go to web calc
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When a number is increased by 9.5%, the result is 58. What is the original number to the nearest tenth?
mario62 [17]

Answer:

50

Step-by-step explanation:

58 - 9.5

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Which of the functions represents a linear function? Explain your reasoning, then determine the rate of change for that function
Andrej [43]

Answer:

Step-by-step explanation:

for Which of the functions represents a linear function? Explain your reasoning, then determine the rate of change for that function over the interval 2≤x≤4.

For a linear function, the rate of change is represented by the parameter m in the slope-intercept form for a line: y=mx+b, and is visible in a table or on a graph.

5 0
3 years ago
6: Abby is making a decoration. When folded, the decoration is a triangular pyramid made of four congruent equilateral triangles
NeTakaya

Answer:

85 square inches  

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo

My answer:

From the question, four congruent equilateral triangles with the following information:

  • The height: 6.06 inches
  • The base : 7 inches

=> The area of the quilateral triangle is:

=1/2*the base*the height

= 1/2*60.6*7

= 21.21 square inches

=> the surface area of Abby's decoration is:

= 4 * The area of the quilateral triangle

= 4*21.21

= 84.84 square inches  

≈ 85 square inches  

Hope it will find you well.

7 0
4 years ago
Which 2 values of x are roots of the polynomial below?
Alexxx [7]

Given:

The given polynomial is:

f(x)= 3x^{2}-3x+1

To find the roots of the given polynomial.

To find the roots we have to take f(x) = 0

So,

3x^{2} -3x+1 = 0

Formula

By quadratic formula, the root of the equation ax^{2} +bx+c = 0 is,

x = \frac{-b+\sqrt{b^{2}-4ac } }{2a} and \frac{-b-\sqrt{b^{2} -4ac} }{2a}

Now,

Putting, a=3, b=-3, c=1 we get,

x = \frac{3+\sqrt{3^{2}-4(3)(1) } }{(2)(3)} and \frac{3-\sqrt{3^{2}-4(3)(1) } }{(2)(3)}

x = \frac{3+\sqrt{-3} }{6} and x=\frac{3-\sqrt{-3} }{6}

Hence,

The values of the roots of the given polynomial arex=\frac{3+\sqrt{-3} }{6} and x=\frac{3-\sqrt{-3} }{6}

Hence, Option A and F are the correct answer.

5 0
3 years ago
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