Answer:
Step-by-step explanation:
- You're either right or you're wrong. ...
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The general solution of tan(b·x) = 2, given that the smallest positive solution is x = 0.3, is presented as follows;
![\mathbf{ x =0.3 + \dfrac{n \cdot \pi}{b}}](https://tex.z-dn.net/?f=%5Cmathbf%7B%20x%20%3D0.3%20%2B%20%20%5Cdfrac%7Bn%20%5Ccdot%20%5Cpi%7D%7Bb%7D%7D)
The given smallest positive solution of tan (b·x) = 2 is x = 0.3
The general solution of tan (b·x + c) = m, is given as follows;
![\mathbf{x = \dfrac{\alpha - c}{b} + n \cdot \dfrac{\pi}{b}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%20%3D%20%5Cdfrac%7B%5Calpha%20%20-%20c%7D%7Bb%7D%20%20%2B%20n%20%5Ccdot%20%5Cdfrac%7B%5Cpi%7D%7Bb%7D%7D)
α = arctan(m) = x₀
The minimum positive value of the general solution is therefore presented as follows;
![x_{min \ positive} = \dfrac{\alpha - c}{b} + 0 \times \dfrac{\pi}{b} = \dfrac{\alpha - c}{b}](https://tex.z-dn.net/?f=x_%7Bmin%20%5C%20positive%7D%20%3D%20%5Cdfrac%7B%5Calpha%20%20-%20c%7D%7Bb%7D%20%20%2B%200%20%5Ctimes%20%5Cdfrac%7B%5Cpi%7D%7Bb%7D%20%3D%20%5Cdfrac%7B%5Calpha%20%20-%20c%7D%7Bb%7D)
![\mathbf{x_{min \ positive} = \dfrac{\alpha - c}{b}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx_%7Bmin%20%5C%20positive%7D%20%3D%20%5Cdfrac%7B%5Calpha%20%20-%20c%7D%7Bb%7D%7D)
In the given function, tan (b·x), we therefore, have;
c = 0, m = 2, ![\dfrac{\alpha - c}{b} = 0.3](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Calpha%20%20-%20c%7D%7Bb%7D%20%3D%200.3)
The general solution of tan(b·x) = 2, is therefore;
![\mathbf{x =0.3 + \dfrac{n \cdot \pi}{b}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%20%3D0.3%20%2B%20%20%5Cdfrac%7Bn%20%5Ccdot%20%5Cpi%7D%7Bb%7D%7D)
Learn more about the general solution of a sine function here:
https://brainly.in/question/1549935
Answer:
he spent $68 without the fees and $32 on fees
Step-by-step explanation:
Answer:
the one which is not a proportional relationship is y=x