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lesya [120]
3 years ago
12

Someone help me please

Mathematics
2 answers:
Alika [10]3 years ago
5 0
121+3600=c²
3721=c²
c=61
The hypotenuse of the triangle is 61 feet<span />
jekas [21]3 years ago
3 0
General formula to find hypotenuse is
c² = a² + b²
a and b is the side on the right angle, c is hypotenuse

Input the numbers
c² = a² + b²
c² = 60² + 11²
c² = 3,600 + 121
c² = 3,721
c = √3,721
c = 61

The hypotenuse is 61 feet
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Determine the common difference for each arithmetic sequence 10.5, 13, 15.5, 18
andrew11 [14]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Sophia is 12 years old. Her Uncle Reynald tells her that if she adds 5 to her age, multiplies the sum by 3, and then subtracts 4
sasho [114]

Answer:

Her uncle's age = 47 years

Step-by-step explanation:

Sophia = 12 years old

Her Uncle Reynald tells her that if she adds 5 to her age,

= 12 + 5

multiplies the sum by 3

= (12 + 5) × 3

and then subtracts 4 from the product

= {(12 + 5) × 3} - 4

she will find his age

{(12 + 5) × 3} - 4

= (17 × 3) - 4

= 51 - 4

= 47

Her uncle's age = 47 years

Sophia wrote:

12 + 5 × 3 − 4

Using PEMDAS

P - product

E - exponent

M - multiplication

D - division

A - addition

S - subtraction

Sophia's expression can be written as = 12+(5*3)-4

= (12 + 15) - 4

= 27 - 4

= 23

Sophia's expression is wrong

8 0
3 years ago
Which expression can be used to find 532 divided by 4?
user100 [1]

C: (500 divided by 4)+(30 divided by 4)+2

Expanded form or expanded notation is a way of writing numbers to see the math value of individual digits. When numbers are separated into individual place values and decimal places they can also form a mathematical expression. 532 ÷ 4 in expanded notation form is (500 divided by 4)+(30 divided by 4)+2

4 0
2 years ago
6. What is the value of x?
givi [52]

Answer:

D. 14

Step-by-step explanation:

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6 0
3 years ago
Plss answer!! <br>MERRY Christmas!!! <br>Critical Question. AAAAA​
liberstina [14]

Answer:

Step-by-step explanation:

abc = 1

We have to prove that,

\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1

We take left hand side of the given equation and solve it,

\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}

Since, abc = 1,

\frac{1}{c}=ab and c = \frac{1}{ab}

By substituting these values in the expression,

\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}=\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+ab}+\frac{1}{1+\frac{1}{ab}+\frac{1}{a}}

                                       =\frac{b}{b+ab+1}+\frac{1}{1+b+ab}+\frac{ab}{ab+1+b}

                                       =\frac{1+b+ab}{1+b+ab}

                                       =1

Which equal to the right hand side of the equation.

Hence, \frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1

5 0
3 years ago
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