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3 years ago

Use a trigonometric identity to find the indicated value in the specified quadrant.

1 answer:

7 0

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_______________

Cosine and secant functions are reciprocal, which means

$\mathsf{sec\,\theta=\dfrac{1}{cos\,\theta}}$

So, if $\mathsf{cos\,\theta=\dfrac{3}{8},}$ then

$\mathsf{sec\,\theta=\dfrac{1}{~\frac{3}{8}~}}\\\\\\
\mathsf{sec\,\theta=\dfrac{8}{3}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: cosine secant cos sec relation reciprocal trig trigonometry

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The figure to the right has its congruent segments marked. Find the measure of AB.

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Answer:

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Frank is making a pennant in the shape of a triangle for his senior class photo. He wants the base length of this triangle to be

Sav [38]

Answer:

Height should be ≤ 9 inches.

Step-by-step explanation:

Given:

Frank is making a pennant in the shape of a triangle for his senior class photo.

Base of triangle = 6 in

Area of triangle ≤ 27 $in^2$

Let height of the triangle be h

Now we now that,

Area of triangle = $\frac{1}{2}\times base \times height$

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2 years ago

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2 years ago

Read 2 more answers

Urgent

Damm [24]

The result of our calculations about the rate and time are:

r=d/t

200000m/hr

200km/hr

km/hr

Rate can be regarded as the given object with respect to time.

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t= 4 hours

We were given the formula as (d = rt)

d= distance

r = rate

t = time

We can make our calculations as:

part a:

r=d/t

part b:

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part c:

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part d:

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brainly.com/question/8728504

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2 years ago

According to the National Association of Colleges and Employers, the average starting salary for new college graduates in health

katen-ka-za [31]

Answer:

a) The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

b) The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

c) The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

d) A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

Step-by-step explanation:

a. What is the probability that a new college graduate in business will earn a starting salary of at least $65,000?

For college graduates in business, the salary distributes normally with mean salary of $53,901 and standard deviation of $15,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

$z=\frac{x-\mu}{\sigma} =\frac{65000-53901}{15000} =0.74$

The probability is then

$P(X>65,000)=P(z>0.74)=0.22965$

The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

b. What is the probability that a new college graduate in health sciences will earn a starting salary of at least $65,000?

For college graduates in health sciences, the salary distributes normally with mean salary of $51,541 and standard deviation of $11,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

$z=\frac{x-\mu}{\sigma} =\frac{65000-51541}{11000} =1.22$

The probability is then

$P(X>65,000)=P(z>1.22)=0.11123$

The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

c. What is the probability that a new college graduate in health sciences will earn a starting salary less than $40,000?

To calculate the probability of earning less than $40,000, we can calculate the z-value:

$z=\frac{x-\mu}{\sigma} =\frac{40000-51541}{11000} =-1.05$

The probability is then

$P(X$

The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

d. How much would a new college graduate in business have to earn in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences?

The z-value for the 1% higher salaries (P>0.99) is z=2.3265.

The cut-off salary for this z-value can be calculated as:

$X=\mu+z*\sigma=51,541+2.3265*11,000=51,541+25,592=77,133$

A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

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3 years ago