1.volume*filling a shape*
2.volume
3.area
4.volume
5.area
Answer:
114
Step-by-step explanation:
23 × 5 = 100 + 15 = 115
2 + 115 - 3 = 2 + 112 = 114
Sol. (1) Prime factors of 26 = 2 x 13
Prime factors of 91 = 7 x 13
Hence, HCF = Common factors between 26 and 91 =13 and LCM=13x2x7=182
Now product of numbers 26 and 91
= 26 x 91 = 2366 and Product of HCF and LCM = 13 x 182 = 2366
So, it verify that product of two numbers = Product of HCF and LCM.
(2) Prime factors of 510 = 2 x 3 x 5 x 17
Prime factors of 92 = 2 x 2 x 23
Hence,HCF=2 and LCM=2×2×3 × 5×17×23 =23460
Now product of Numbers 510 and 92 = 46920 and product of HCF and LCM = 2 x 23460= 46920
Hence, verified that product of two numbers 18 equal to product of their HCF and LCM.
(3) Prime factors of336 = 2 x 2 x 2 x 2 x 3 x 7
Prime factors of 54 = 2 x 3 x 3 x 3
Hence, HCF (Product of common factors of 336 and 54)
=2 x 3=6
And LCM (Product of all common factors with remaining factors)
=(2 x 3)x 2 x 2 x 2 x 3 x 3 x 7=3024
Now, product of numbers 336 and 54 = 336 x 54 = 18144
and product of HCF and LCM = 6 x 3024 = 18144
Hence, product of two numbers: Product of HCF and LCM.
Answer:
x=2 x=-3
Step-by-step explanation:
4x2+3x=24-x
Subtract 24 from each side
4x^2 +3x -24 = 24-24 -x
4x^2 +3x -24 = -x
Add x to each side
4x^2 +3x+x -24 = -x+x
4x^2 +4x -24 = 0
Factor out a 4
4(x^2 +x -6) = 0
Divide by 4
x^2 +x -6 =0
Factor
What 2 numbers multiply to -6 and add to 1
-2*3 = -6
-2+3 =1
(x-2) (x+3) =0
Using the zero product property
x-2 =0 x+3 =0
x-2+2=0+2 x+3-3=0-3
x=2 x=-3
then