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mestny [16]
3 years ago
15

Here are some summary statistics about the number of accounts that follow some bands on social media. mean: 15,976 followers med

ian:16,432 followers standard deviation:3,279 followers Q1:13,796 Q3:19,070 IQR:5,274 followers Give an example of a number of followers that a relatively unknown band might have that would be considered an outlier for this data. Explain or show your reasoning. Your answer:
Mathematics
2 answers:
docker41 [41]3 years ago
7 0

Answer:

Ok, I have no Idea about this??

Step-by-step explanation:

However, If possible, can I have brainliest.

Lelu [443]3 years ago
5 0

Answer:

what kind of math is this

Step-by-step explanation:

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A on Edg.

Step-by-step explanation:

Took the Test

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At a restaurant, the waiter brings 6 sub sandwiches for 8 children to share so that everyone gets the same amount. How much can
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3/4 of a sandwich for each sandwich will amount to 6 sandwiches and 8 children can eat
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2 years ago
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A used automobile dealership recently reduced the price of a used compact car by 6%. If the price of the car before discount was
Alchen [17]

Answer:

The discount = $1,128

New price = $17,672

Step-by-step explanation:

Price of car before discount = $18,800

Discount given = 6% of price of car

Discount value in dollars = 6% of $18,800 = 6/100*$18,800 = $1,128

Thus, the discount is $1,128

New price = Price of car before discount - discount = $18,800- $1,128

New price = $17,672

7 0
3 years ago
Hello!!! What is the square root of 35???
saveliy_v [14]

Answer:

sqrt(35) ≈5.916079783

Step-by-step explanation:

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In preparation for an earnings report, a large retailer wants to estimate p= the proportion of annual sales
mr Goodwill [35]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size and the estimate are given by:

n = 161, \pi = \frac{37}{161} = 0.2298

Hence:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 - 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.1648

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 + 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.2948

The 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

More can be learned about the z-distribution at brainly.com/question/25890103

5 0
3 years ago
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