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mestny [16]
3 years ago
15

Here are some summary statistics about the number of accounts that follow some bands on social media. mean: 15,976 followers med

ian:16,432 followers standard deviation:3,279 followers Q1:13,796 Q3:19,070 IQR:5,274 followers Give an example of a number of followers that a relatively unknown band might have that would be considered an outlier for this data. Explain or show your reasoning. Your answer:
Mathematics
2 answers:
docker41 [41]3 years ago
7 0

Answer:

Ok, I have no Idea about this??

Step-by-step explanation:

However, If possible, can I have brainliest.

Lelu [443]3 years ago
5 0

Answer:

what kind of math is this

Step-by-step explanation:

You might be interested in
In the triangle below,
defon

Answer: y ≈ 10.6 cm

Step-by-step explanation:

The cosine function relates the adjacent side to the hypotenuse in a right triangle. The side adjacent to the 20° angle is 10 cm.

cos(20°) = (10 cm)/y

y = (10 cm)/cos(20°)

y ≈ 10.6 cm

3 0
3 years ago
Do male and female servers work the same number of hours? A sample of 25 female servers worked an average of 26 hours per week,
Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

Given that

Group   Group One     Group Two  

Mean       26.00 23.00

SD                 2.00 4.00

SEM         0.40 1.21

N                     25     11    

where group I represents female servers and group II male servers.

We have to calculate confidence interval for 90% for difference in means

The mean of Group One minus Group Two equals 3.00

df = 34  

 standard error of difference = 0.993

t critical = 2.034 for 90% df 34

Hence confid. interval at 90%

=Mean diff ±2.034 * std error of diff

= (0.98, 5.02)

5 0
3 years ago
Solve for x. Tx-ux=3t
Veronika [31]
<span>x(t-u) = 3t
dividing both sides by (t-u):
So.. </span><span><em>x = 3t/(t-u)</em></span>
6 0
3 years ago
List the ordered pairs in the equivalence relations produced by these partitions of {a, b, c, d, e, f, g}: a) {a,b},{c,d},{e,f,g
finlep [7]

Answer:

a)  {a,b} , {c,d} , {e,f,g},{a , b } = {(a,a) (b,b) (a,b) (b,a)},{c , d } = {(c,c) (d,d) (c,d) (d , c) } ,{e,f,g} = {(e,e) (e,f)  (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f)(g,g)}  

b) { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)

c)  {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

Step-by-step explanation:

a) {a,b} , {c,d} , {e,f,g}

  {a , b } = {(a,a) (b,b) (a,b) (b,a)}

  {c , d } = {(c,c) (d,d) (c,d) (d , c) }

  {e,f,g} = {(e,e) (e,f)  (f,e)  (e,g) (f,f) (f,g) ( g,e) (g,f) (g,g)}  

b) {a} ,{b},{c,d} ,{e,f},{g}

     { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)}

c)  {a,b,c,d},{e,f,g}

   {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

4 0
3 years ago
A bag contains 6 red balls and 3 blue balls. 4 balls are selected at random. find the probability of selecting 4 red balls.
geniusboy [140]
Assuming that the balls are not replaced; 

\frac{6}{9}* \frac{5}{8}* \frac{4}{7}* \frac{3}{6}= 5/42 

(the numbers are decreasing in the denominator as you are presumably taking out the red balls. In the denominator, there is one less ball each time since you took out a red one). 

Therefore, the probability of selected 4 red balls consecutively without replacement is 5/42. 

Hope I Helped :) 

4 0
3 years ago
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