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Nana76 [90]
3 years ago
12

Jim wanted to find out what the audience thought about the debate. After the event, Jim stood at the exit to survey every fifth

guest. Was this a random or a biased sample and why?
Mathematics
1 answer:
balu736 [363]3 years ago
7 0

Answer: D. This was a random sample. It may have included anyone in attendance.

Step-by-step explanation:

The options are:

A. This was a biased sample. Jim should interview all in attendance.

B. This was a census. Any guest may have participated.

C. This was a random sample. It may not have included anyone in attendance.

D. This was a random sample. It may have included anyone in attendance.

A random sampling is simply referred to as a subset of individuals that are picked from a larger set of individuals.

With regards to the question, Jim wanted to find out what the audience thought about the debate and after the event, he stood at the exit to survey every fifth guest.

This means that it was a random sampling and anyone could have been picked, the sampling wasn't bias.

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The test statistic of zequals2.32 is obtained when testing the claim that pgreater than0.3. a. Identify the hypothesis test as b
Sonja [21]

Answer:

a) We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.3  

Alternative hypothesis:p > 0.3  

Right tailed test

b) p_v =P(z>2.32)=0.0102  

c) So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

Step-by-step explanation:

Part a: Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.3  

Alternative hypothesis:p > 0.3  

Right tailed test

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

For this case the statistic is given by z_{calc}= 2.32

Part b: Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.32)=0.0102  

Part c

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

6 0
3 years ago
Simplify. 32 + 1 x 2 (1).8 (2).20 (3).14 (4).11​
pshichka [43]

Answer:

31.11

Step-by-step explanation:

simplify the expression

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How many solutions are there for the system shown below?<br> 2x² + y2 = 33<br> x2 + y + 2y=19
Doss [256]

Answer:2 max because exponet

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3 years ago
A flagpole stands in the middle of a flat, level field. 50 feet away from its base, a surveyor measures the angle to the top of
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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Just need someone to check my answer
mixas84 [53]
<span>The correct answer is 216x</span>⁶<span>y</span>⁵<span>.

Explanation:
The first thing we do is raise the last monomial to the third power.

(4xy)(2x</span>²<span>y)(3xy)</span>³
<span>=(4xy)(2x</span>²<span>y)(3</span>³<span>x</span>³<span>y</span>³<span>)
=4xy(2x</span>²<span>y)(27x</span>³<span>y</span>³<span>).

Now we can multiply the first two monomials. When we multiply powers with the same base, we add the exponents:
8x</span>³<span>y</span>²<span>(27x</span>³<span>y</span>³<span>).

We multiply these last two monomials, again adding the exponents:
216x</span>⁶<span>y</span>⁵<span>.</span>
3 0
3 years ago
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