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kenny6666 [7]
4 years ago
8

Find the recursive formula of the arithmetic sequence 14,30,46,62

Mathematics
1 answer:
dexar [7]4 years ago
4 0

Answer:

a_n=a_{n-1}+16

Step-by-step explanation:

The given arithmetic sequence is

14,30,46,62

The first term of this sequence is

a_1=14

The common distance is obtained by subtracting a subsequent term from a previous term;

d=30-14

The common difference is

d=16

The recursive formula is given by:

a_n=a_{n-1}+d

We now plug in the known value for the common difference to get;

a_n=a_{n-1}+16

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En una panadería se elaboraron 140 panes diarios, el 25% son conchas, 10% cortadillos, 40% donas y 25% bolillos. Cada pieza de p
torisob [31]

Answer:

Se obtuvo $ 448 de ganancia por la venta de donas.

Se obtuvo $ 280 de ganancia por la venta de bolillos.

Step-by-step explanation:

1) <em>¿Cuanta ganancia se obtuvo en la venta de donas?</em>

La ganancia es el producto del porcentaje producido de donas, expresado como razón, el precio unitario de la dona y el total producido de panes. Es decir:

C = \frac{40\,donas}{100\,panes}\times (140\,panes)\times \left(8\,\frac{USD}{dona} \right)

C = 448\,USD

Se obtuvo $ 448 de ganancia por la venta de donas.

2) <em>¿Cuanta ganancia se obtuvo en la venta de bolillos?</em>

La ganancia es el producto del porcentaje producido de bolillos, expresado como razón, el precio unitario del bolillo y el total producido de panes. Es decir:

C = \frac{25\,bolillos}{100\,panes}\times (140\,panes)\times \left(8\,\frac{USD}{bolillo}\right)

C = 280\,USD

Se obtuvo $ 280 de ganancia por la venta de bolillos.

3 0
3 years ago
A tire manufacturer knows that 5% of tires contain a defect, and the presence of a defect is independent from tire to tire.
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Answer:

0.021

Step-by-step explanation:

yep

3 0
3 years ago
Read 2 more answers
The USDA conducted tests for salmonella in produce grown in California. In an independent sample of 252 cultures obtained from w
Marat540 [252]

Answer:

 The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

Step-by-step explanation:

From the question we are told that

   The first  sample size is n_1   =  252

    The number that tested positive is  k_1  =  18

     The second sample size is  n_2   =  476

     The number that  tested positive is  k_2 =  20

     The level of significance is  \alpha  = 0.01

Generally the first sample proportion is mathematically represented as

      \^ p _1 =  \frac{k_1 }{ n_1 }

=>    \^ p _1 =  \frac{18 }{ 252 }

=>    \^ p _1 = 0.071

Generally the second sample proportion is mathematically represented as

      \^ p _2 =  \frac{k_2 }{ n_2 }

=>    \^ p _2 =  \frac{20 }{ 476}

=>    \^ p _2 = 0.042

The  null hypothesis is            H_o  :  p_1 - p_2 = 0

The alternative hypothesis is  H_a :  p_1 - p_2 \ne 0

Generally the test statistics is mathematically represented

       z =  \frac{ \^ p_1 - \^ p_2  -  ( p_ 1 - p_2 )}{ \sqrt{\frac{\^ p_1 (1-\^ p_1)}{ n_1  } + \frac{\^ p_2 (1-\^ p_2)}{ n_2  }  } }

=>    z =  \frac{ 0.071 - 0.042  - 0 }{ \sqrt{\frac{0.071  (1-0.071)}{  252  } + \frac{0.042 (1-\^ 0.042)}{ 476  }  } }

=>    z =  1.56

From the z table  the area under the normal curve to the right corresponding to  1.56   is  

        P(Z >  1.56 ) =0.05938

Generally the p-value is mathematically represented as

         p-value =  2 * P(Z >  1.56 )

=>      p-value = 2 *  0.05938

=>      p-value = 0.1188

From the value obtained we see that   p-value  >  \alpha hence

  The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

 

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