Question

What are the coordinates of T′ for the transformation (T(–3, 1)° D4 )(ΔTUV) of T(–7, –6), U(–8, 3), and V(2, 1)?

Answer 1

Answer:

$T'=(-31,-23)$

Step-by-step explanation:

1. Since this is a Dilation with a scale factor of 4 (D4) let's plot the triangle TUV.

Check the picture 1

2. The Center of Dilation of this transformation is at the center. But the transformation is given by a scale factor of 4 and adding to (-3,1)

So,

$T'= 4(-7,-6) +(-3,1)=(-28,-24)+(-3,1) \therefore T'=(-31,-23)\\U'=4(-8,3)+(-3,1)=(-32,12)+(-3,1) \therefore U'=(-35,13)\\V'=4(2,1) +(-3,1)=(8,4)+(-3,1) \therefore V'= (5,5)$

3. Back to the graph to visualize this transformation a Dilation, an enlargement and the transformation combined.