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3 years ago

How many solutions does the equation have?

Mathematics

2 answers:

nikklg [1K]3 years ago

6 0

B which equals -55 I think this is right

irina1246 [14]3 years ago

3 0

Since the coefficients of d are not equal, then there can only be one solution

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marishachu [46]

Answer:

Step-by-step explanation:

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3 years ago

Only I need help with 1,2 and three please

Mazyrski [523]

Is that the whole thing?

4 0

3 years ago

There are 40 marbles in a bag if 14 if the marbles are red what percent of the marbles in the bag are red

Neporo4naja [7]

$\frac{14}{40} \times 100\%=\frac{7 \times 2}{20 \times 2} \times 100\%=\frac{7}{20} \times 100\%=7 \times \frac{100}{20} \%=7 \times 5\%=35\%$

35% of the marbles are red.

4 0

3 years ago

Please Help!!

Genrish500 [490]

Given

$a\sqrt{x+b}+c=d$

we have

$\sqrt{x+b}=\dfrac{d-c}{a}$

Squaring both sides, we have

$x+b=\dfrac{(d-c)^2}{a^2}$

And finally

$x=\dfrac{(d-c)^2}{a^2}-b$

Note that, when we square both sides, we have to assume that

$\dfrac{d-c}{a}>0$

because we're assuming that this fraction equals a square root, which is positive.

So, if that fraction is positive you'll actually have roots: choose

$a=1,\ b=0,\ c=2,\ d=6$

and you'll have

$\sqrt{x}+2=6 \iff \sqrt{x}=4 \iff x=16$

Which is a valid solution. If, instead, the fraction is negative, you'll have extraneous roots: choose

$a=1,\ b=0,\ c=10,\ d=4$

and you'll have

$\sqrt{x}+10=4 \iff \sqrt{x}=-6$

Squaring both sides (and here's the mistake!!) you'd have

$x=36$

which is not a solution for the equation, if we plug it in we have

$\sqrt{x}+10=4 \implies \sqrt{36}+10=4 \implies 6+10=4$

Which is clearly false

7 0

3 years ago

Which graph represents the function f(x) = |x|?

Brut [27]

Answer:

Step-by-step explanation:

the first one

3 0

3 years ago

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