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iogann1982 [59]
3 years ago
7

For what value of x is line a parallel to line b? Enter your answer in the box. x =

Mathematics
1 answer:
Trava [24]3 years ago
3 0
Where are the values of B?
In order for X to be parallel to B you must have the values for B first. Then they will have the same slope.
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Suppose that when your friend was born, your friend's parents deposited $7000 in an account paying 6.3% interest compounded quar
NNADVOKAT [17]

Step-by-step explanation:

okay I think you can solve this question now ☺️

7 0
3 years ago
If there are 22 successes in a sample with a size of 40, what is the sample
patriot [66]

Answer:

A

Step-by-step explanation:

22 successes out of a group of 40 means 22/40 were good. Now, simplify 22/40. Both can be divided by 2.

22/2 = 11

40/2 = 20

Now you have 11/20. Put this in decimal form and you have 0.55

3 0
3 years ago
Read 2 more answers
You graph the function f(x)=-|×|-12
Firlakuza [10]

Answer:

See attachment

Step-by-step explanation:

We want to graph f(x)=|x|-12 on the interval -10 to 10.

Let g(x)=|x| be the parent absolute value function.

We can easily graph f(x)=|x|-12, if we use translation.

When the parent function is shifted downwards by 12 units, we obtain the graph of f(x)=|x|-12.

The parent function is a v-shaped graph with vertex at the origin.

We shift the parent function down so that its vertex is now at (0,-12) to get the graph of f(x)=|x|-12 .

See attachment for the graph of f(x)=|x|-12  on the specified interval.

7 0
3 years ago
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3 x 2 1/2= ?????????????????/<br> Welp
igor_vitrenko [27]

Answer:15/2

Step-by-step explanation:

3 0
3 years ago
Find the inverse of the matrix , if it exists
Montano1993 [528]

Answer:

So, option A is correct.

Step-by-step explanation:

To find the inverse of the matrix, the formula is:

A^{-1} = 1/|A| * Adj A

Inverse of the matrix exists if |A| does not equal to 0

|A| = 7 * 9 -( -2 * -10)

|A| = 63 - 20

|A| = 43

AS |A| ≠ 0

so inverse exist.

now finding Adj A

Adj A = \left[\begin{array}{cc}9&2\\10&7\end{array}\right]

\left[\begin{array}{cc}9/43&2/43\\10/43&7/43\end{array}\right]

So, option A is correct.

8 0
3 years ago
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