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matrenka [14]
3 years ago
12

You are given a flask with standard liquid media containing a population of S. pombe cells that have a temperature sensitive mut

ation of a gene that causes complete loss of function of the gene product at the restrictive temperature. The flask had been incubating at the permissive temperature in the dark before it was given to you, and the cells in the flask were replicating asynchronously with respect to the stage of the cell cycle. The mutated gene in this strain of yeast encodes an essential component of a UV-mediated DNA damage checkpoint. Which FACS plot (see attached figure) best represents how cells in this flask would appear following growth for 30 min at the restrictive temperature ? (Note, assume that FACS plot #1 shows analysis of a population of S. pombe replicating asynchronously (i.e. each cell within a population is at a random stage of the cell cycle) in culture. In the rich media assume the yeast have a cell cycle time of 100 min, with G1=50 min; S = 25 min; G2 = 15 min and M = 10 min).a. #2 b. #3 c. #4 d. #5 e. #6
Biology
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

The best graphic that represent the growth of the cells is the plot #2

Explanation:

Using flow cytometry, a cell cycle analysis study uses a dye for DNA binding, and it is fluorescently labeled to allow stoichiometry of DNA to bind to DNA content.

During the phases, the DNA content will be:

G0 / G1 phase = 2n (diploid).

Phase S = 2n (duplication of DNA content)

G2 / M phase = 4n (content of tetraploid DNA 4n)

When cells are growing, a mutation will occur in the gene. This would lead to the cell cycle being unlikely to stop due to the checkpoint gene mutation, causing it to be unable to detect any damage. the cell cycle continues normally.

In exercise, cells that were in the G1 phase will reach the S phase. Therefore, the peak of that phase will be increased, and the peak of the G1 phase will decrease. The cells that were in the S phase will go to the G2 / M phase, which will increase the peak.

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George on one pair of his chromosomes has STRs of lengths 6 and 7, Stephen (his father) STRs of lengths 3 and 6, and Mary (his m
JulijaS [17]

Answer:

Stephen is not his biological father.

Explanation:

DNA fingerprinting is a technique use to determine the DNA sequence of an individual organism. Short tandem repeats are unique among the individuals ans used to identify the individual in population.

The George DNA fingerprinting shows that he has STRs length of 6 and 7. Stephen's STRs does not match with his son George whereas Mary shows some similarities with George STRs. This indicates that Stephen is not the biological father of George because the biological father's STRs must match with the children STRs.

Thus, the correct answer is option (a).

4 0
3 years ago
Which indicators are living and non-living?
bulgar [2K]
Living indicators are species that are sensitive to changes in the environment. For example air pollution can be monitored by looking at lichen, which are sensitive to sulphur dioxide in the air. The number of lichen at a particular location indicates how clear the air is. Similarly, mayfly larvae are good indicators for water pollution because they're sensitive to the concentration of dissolved oxygen in water.

Non-living indicators are things like satellites which can measure the temperature of the sea surface, weather stations that measure atmospheric temperature, rain gauges to measure rainfall, and dissolved oxygen meters to measure concentration of dissolved oxygen in water. 
7 0
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A series of Hfr strains that have genotype m+ n+ o+ p+ q+ r+ are mixed with an F− strain that has genotype m− n− o− p−
ki77a [65]

my brain can't process this lol

6 0
3 years ago
Explain why mutations may or may not affect phenotype
Svetlanka [38]

Answer:

Explanation:

Mutations may or may not affect the phenotype because they can occur in coding or non coding areas of the DNA. If they occur in coding areas of the DNA, the protein that is coded in that part could be processed incompletely or have a different amino-acid in some part of its structure, this would affect the phenotype. If they occur in non coding areas, this would have no effect on the phenotype.

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Which of these engulf bacteria and break them down
dolphi86 [110]

Answer:

Phagocytes

Explanation:

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