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nikklg [1K]
3 years ago
9

A summer camp cookout is planned for the campers and their families. There is room for 450 people. Each adult costs $7, and each

camper costs $4. There is a maximum budget of $1,150. Write the system of inequalities to represent this real-world scenario, where x is the number of adults and y is the number of campers. x + y ≤ 1,150 7x + 4y ≤ 450 x + y ≤ 450 7x + 4y ≤ 1,150 x + y ≤ 1,150 4x + 7y ≤ 450 x + y ≤ 450 4x + 7y ≤ 1,150
Mathematics
1 answer:
Tanya [424]3 years ago
3 0

Answer:

\left\{\begin{array}{l}x+y\le 450\\7x+4y\le 1,150\end{array}\right.

Step-by-step explanation:

Let  x be the number of adults and y be the number of campers.

There are rooms for 450 people, so

x+y≤450.

Each adult costs $7, then x adults cost $7x.

Each camper costs $4, then y campers cost $4y.

There is a maximum budget of $1,150, so

7x+4y≤1,150

Hence, you get the system of two inequalities:

\left\{\begin{array}{l}x+y\le 450\\7x+4y\le 1,150\end{array}\right.

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Step-by-step explanation:

a. Given:  

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Formula sample size:

p known: n = [z_\alpha/2 ]^2*pq/E^2

                   = [z_\alpha/2 ]^2*p(1-p)/E^2

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For confidence level 1 –\alpha= 0.95, determine z_\alpha/2 = z_o.025 using table 1 (look up 0.025 in the table, the z-score is then the found z-score with opposite sign):  

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n =[z_\alpha/2 ]^2*p(1-p)/E^2

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