Answer:
-12
Step-by-step explanation:
Problem 2
Plot point L anywhere that isn't on segment JK. Draw a line through point L. I find it helps to make the lines parallel.
Next, use a compass to measure the width of segment JK. Keeping this same width, transfer the nonpencil end of the compass to point L. Draw an arc that crosses the line through L.
Mark this intersection point M. Lastly, use a pen or marker to form segment LM and erase everything else of that line.
======================================================
Problem 3
The ideas of the previous problem will be used here. We copied segment JK to form congruent segment LM. So JK = LM.
The same steps will be used to form segment GN where GN = EF. In other words, segment GN is a perfect copy of segment EF.
If you repeat these steps again, you'll get another segment of the same length. This segment goes from point N to point H. So NH = GN = EF
Then we can say,
GH = GN + NH
GH = EF + EF
GH = 2*EF
Answer:
Please check the explanation.
Step-by-step explanation:
Given the function
Putting all the values of y=9, 6, 0, and -3 to complete the table
FOR y=9
putting y=9
switch sides
subtract 3 from both sides
Hence,
when y=9, x=4
FOR y=6
putting y=6
switch sides
subtract 3 from both sides
Hence,
when y=6, x=2
FOR y=0
putting y=0
switch sides
subtract 3 from both sides
Hence,
when y=0, x=-2
FOR y=-3
putting y=-3
switch sides
subtract 3 from both sides
Hence,
when y=-3, x=-4
Hence, the table becomes:
x y
9 4
6 2
0 -2
-3 -4
Answer:
3 = 4m or 0.75 = m
Step-by-step explanation:
12.6 + 4m = 9.6 + 8m
Subtract 4m from both sides of the equation
12.6 = 9.6 + 4m
Subtract 9.6 from both sides of the equation
3 = 4m
Divide by four on both sides of the equation
0.75 = m
I Hope That This Helps! :)
Answer:
2x^2 - x - 15 = 0.
Step-by-step explanation:
In factor form this is
(x + 5/2)(x - 3) = 0
x^2 + 5/2x - 3x - 15/2 = 0
x^2 - 1/2x - 15/2 = 0
Multiply through by 2:
2x^2 - x - 15 = 0.
