Answer:
A. 23+(6-1)x-3
B. 93
Step-by-step explanation:
a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference
6th row = 23 + (6 - 1) x -3
= 23 + (5) x -3
= 23 + (-15)
= 8 - number of boxes in the top row.
b) Sum = N/2[2F + (N - 1) x D]
= 6/2[2*23 + (6 - 1) x -3]
= 3 [46 + (5) x -3 ]
= 3 [46 + -15 ]
= 3 [ 31 ]
= 93 - total number of boxes in the entire display.
Hope this helps! Its 3:25 AM for me too so I know how you feel.
(4v-3w)∧2, Its to the second power so take the exponent 2 and put it on the variables and coefficients so you would have (4∧2)(v∧2)-(3∧2)(w∧2). Then you would do the math and get 16v∧2-9w∧2 than you would add the like terms so you have 25v∧2w∧2.
<span>you have to take arctan(0) to find the value of theta.
tan^-1 (x)=theta </span>
Answer:
The theater has 32 rows
Step-by-step explanation:
The rule of the sum of n terms of an arithmetic sequence is S
=
(a + l), where
- n is the number of the terms
∵ The number of seats per row follows an arithmetic sequence
∵ The first row has 26 seats
∴ a = 26
∵ The last row has 150 seats
∴ l = 150
∵ The theater seats are 2,816
∴ S
= 2,816
→ Substitute these values in the rule of the sum above to find n
∵ 2,816 =
(26 + 150)
∴ 2,816 =
(176)
∴ 2,816 = 88n
→ Divide both sides by 88
∴ 32 = n
∵ n represents the number of the rows
∴ The theater has 32 rows