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gladu [14]
3 years ago
14

A grade has 81 girls and 72 boys. The garde is split into groups that have the same ratio of girls to boys as the whole grade. H

ow many girls are in a group that has 16 boys. Complete the ratio table to solve the problem.
Mathematics
2 answers:
xz_007 [3.2K]3 years ago
6 0

Answer:

18 girls are in the group so 18:16

I think it might be rite but not to to sure

Bezzdna [24]3 years ago
5 0

Answer:

18 is correctcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrectcorrect.

Step-by-step explanation:

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All the questions please
lesya [120]
I don't mean to sound rude or anything but if you go off of the directions up top then you might be able to find the answer these questions are fairly easy and understandable
3 0
3 years ago
Read 2 more answers
Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in
Law Incorporation [45]

Answer:

(a) 900

(b) [567.35 , 1689.72]

(c) [23.82 , 41.11]

Step-by-step explanation:

We are given that a sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms i.e.;

Sample mean, xbar = 290      Sample standard deviation, s = 30  and  Sample size, n = 20

(a) Point estimate of the population variance is equal to sample variance, which is the square of Sample standard deviation ;

                         \sigma^{2}  =  s^{2} = 30^{2}

                          \sigma^{2}  = 900

(b) 90% confidence interval estimate of the population variance is given by the pivotal quantity of  \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

P(10.12 < \chi^{2}__1_9 < 30.14) = 0.90 {At 10% significance level chi square has critical

                                           values of 10.12 and 30.14 at 19 degree of freedom}        

P(10.12 < \frac{(n-1)s^{2} }{\sigma^{2} } < 30.14) = 0.90

P(\frac{10.12}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{30.14}{(n-1)s^{2} } ) = 0.90

P(\frac{(n-1)s^{2} }{30.14} < \sigma^{2} < \frac{(n-1)s^{2} }{10.12} ) = 0.90

90% confidence interval for \sigma^{2} = [\frac{19s^{2} }{30.14} , \frac{19s^{2} }{10.12}]

                                                   = [\frac{19*900 }{30.14} , \frac{19*900 }{10.12}]

                                                   = [567.35 , 1689.72]

Therefore, 90% confidence interval estimate of the population variance is [567.35 , 1689.72] .

(c) 90% confidence interval estimate of the population standard deviation is given by ;

       P(\sqrt{\frac{(n-1)s^{2} }{30.14}} < \sigma < \sqrt{\frac{(n-1)s^{2} }{10.12}} ) = 0.90

90% confidence interval for \sigma = [\sqrt{\frac{19s^{2} }{30.14}}   , \sqrt{\frac{19s^{2} }{10.12}}  ]

                                                 = [23.82 , 41.11]

Therefore, 90% confidence interval estimate of the population standard deviation is [23.82 , 41.11] .

7 0
3 years ago
What is the value of y when x = 1 y = -1 y = -1 y = 2 y = 2 y = 5 y = 5 y = 3
storchak [24]

Answer:

where does it stopes

Step-by-step explanation:

3 0
2 years ago
Solve h=-16t^2+20t+6?​
nikdorinn [45]

i think this is the answer Simplifying h(t) = -16t2 + 20t + 6 Multiply h * t ht = -16t2 + 20t + 6 Reorder the terms: ht = 6 + 20t + -16t2 Solving ht = 6 + 20t + -16t2 Solving for variable 'h'. Move all terms containing h to the left, all other terms to the right. Divide each side by 't'. h = 6t-1 + 20 + -16t Simplifying h = 6t-1 + 20 + -16t Reorder the terms: h = 20 + 6t-1 + -16t

7 0
3 years ago
Given that (-5,-8) is on the graph of f(x), find
Fofino [41]

Answer:

can u give more information than i will answer

Step-by-step explanation:

8 0
3 years ago
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