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3 years ago

I need to be able to show my work to 5x^2-17x+6

Mathematics

1 answer:

jekas [21]3 years ago

8 0

<span>5x^2-17x+6
</span>=(x - 3)(5x - 2)

x-3 = 0 then x =3
5x - 2 =0
5x = 2
x =2/5

answer: x =3 and x =2/5

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Answer:

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Step-by-step explanation:

<u>Step 1: Convert</u>

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Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$

$\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }$

$\mathbf{ YX = \sqrt{(3)^2+(6)^2} }$

$\mathbf{ YX = \sqrt{9+36} }$

$\mathbf{ YX = \sqrt{45} }$

$\mathbf{ YX = \sqrt{9*5} }$

$\mathbf{ YX = 3 \sqrt{5} }$

Thus; the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

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Neeeeeeeeeeeeeeeeed heeeeeeeeeeeeeeeeelp!!!!!!!!!!!!!!!!!!!!!!!!

iren [92.7K]

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