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AveGali [126]
4 years ago
10

Write a ratio as a fraction in simplest form 9ft to 15 yd

Mathematics
1 answer:
Andrews [41]4 years ago
7 0
3/5 because you find what goes into each and simplify. 9/15 each divided by 3. 9/3=3 15/3=5 so 3/5 is your answer.
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To get the 10% discount, a shopper must spend at least $200.
Liula [17]

Answer:

d\geq \$200

Step-by-step explanation:

we know that

To get the 10% discount, a shopper must spend at least $200

so

Let

d ------> represent the spending (in dollars) of a shopper who gets the discount

therefore

The value of d must be greater than or equal to $200

d\geq \$200

5 0
3 years ago
(Multiple choice) Help
Sauron [17]
6 is c, i'm not entirely sure about 7
6 0
3 years ago
Suppose a large shipment of laser printers contained 18% defectives. If a sample of size 340 is selected, what is the probabilit
Anestetic [448]

Answer:

The probability that the sample proportion will be greater than 13% is 0.99693.

Step-by-step explanation:

We are given that a large shipment of laser printers contained 18% defectives. A sample of size 340 is selected.

Let \hat p = <u><em>the sample proportion of defectives</em></u>.

The z-score probability distribution for the sample proportion is given by;

                         Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  }  ~ N(0,1)

where, p = population proportion of defective laser printers = 18%

            n = sample size = 340

Now, the probability that the sample proportion will be greater than 13% is given by = P(\hat p > 0.13)

         P(\hat p > 0.13) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  } > \frac{0.13-0.18}{\sqrt{\frac{0.13(1-0.13)}{340}}  } ) = P(Z > -2.74) = P(Z < 2.74)

                                                                      = <u>0.99693</u>

The above probability is calculated by looking at the value of x = 2.74 in the  table which has an area of 0.99693.

5 0
4 years ago
Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are
jasenka [17]

Answer:

The indicated confidence interval for the difference between the two population means is  (-1.5159, 7.5159)

Step-by-step explanation:

Let the drying times of type A be the first population and the drying times of type B be the second population. Then

We have small sample sizes n_{1} = 11 and n_{2} = 9, besides \bar{x}_{1} = 71.5, s_{1} = 3.4 , \bar{x}_{2} = 68.5 and s_{2} = 3.6. Therefore, the pooled

estimate is given by  

s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(11-1)(3.4)^{2}+(9-1)(3.6)^{2}}{11+9-2} = 12.1822

The 99% confidence interval for the true mean difference between the mean drying time of type A and the mean drying time of type B is given by

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{11}+\frac{1}{9}}, i.e.,

(71.5-68.5)\pm t_{0.005}(3.4903)\sqrt{\frac{1}{11}+\frac{1}{9}}

where t_{0.005} is the 0.5th quantile of the t distribution with (11+9-2) = 18 degrees of freedom. So

3\pm(-2.8784)(3.4903)(0.4495), i.e.,

the indicated confidence interval for the difference between the two population means is  (-1.5159, 7.5159)

5 0
3 years ago
A water pump is filling up a tank in the shape of an inverted cone. The top of the cone has a diameter of 12 meters, and the con
olga_2 [115]

Answer:

  20/(9π) m/min ≈ 0.707 m/min

Step-by-step explanation:

The rate of change of height is the rate of change of volume divided by the surface area. Of course, the surface area is given by πr², where r = d/2 = 3 m.

  dh/dt = (dV/dt)/A = (20 m³/min)/(π(3 m²))

  dh/dt = 20/(9π) m/min ≈ 0.707 m/min

5 0
3 years ago
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