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4 years ago

Write a ratio as a fraction in simplest form 9ft to 15 yd

Mathematics

1 answer:

Andrews [41]4 years ago

7 0

3/5 because you find what goes into each and simplify. 9/15 each divided by 3. 9/3=3 15/3=5 so 3/5 is your answer.

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To get the 10% discount, a shopper must spend at least $200.

Liula [17]

Answer:

$d\geq \$200$

Step-by-step explanation:

we know that

To get the 10% discount, a shopper must spend at least $200

Let

d ------> represent the spending (in dollars) of a shopper who gets the discount

therefore

The value of d must be greater than or equal to $200

$d\geq \$200$

5 0

3 years ago

(Multiple choice) Help

Sauron [17]

6 is c, i'm not entirely sure about 7

6 0

3 years ago

Suppose a large shipment of laser printers contained 18% defectives. If a sample of size 340 is selected, what is the probabilit

Anestetic [448]

Answer:

The probability that the sample proportion will be greater than 13% is 0.99693.

Step-by-step explanation:

We are given that a large shipment of laser printers contained 18% defectives. A sample of size 340 is selected.

Let $\hat p$ = the sample proportion of defectives.

The z-score probability distribution for the sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }$ ~ N(0,1)

where, p = population proportion of defective laser printers = 18%

n = sample size = 340

Now, the probability that the sample proportion will be greater than 13% is given by = P( $\hat p$ > 0.13)

P( $\hat p$ > 0.13) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }$ > $\frac{0.13-0.18}{\sqrt{\frac{0.13(1-0.13)}{340}} }$ ) = P(Z > -2.74) = P(Z < 2.74)

= 0.99693

The above probability is calculated by looking at the value of x = 2.74 in the table which has an area of 0.99693.

5 0

4 years ago

Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are

jasenka [17]

Answer:

The indicated confidence interval for the difference between the two population means is (-1.5159, 7.5159)

Step-by-step explanation:

Let the drying times of type A be the first population and the drying times of type B be the second population. Then

We have small sample sizes $n_{1} = 11$ and $n_{2} = 9$ , besides $\bar{x}_{1} = 71.5$ , $s_{1} = 3.4$ , $\bar{x}_{2} = 68.5$ and $s_{2} = 3.6$ . Therefore, the pooled

estimate is given by

$s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(11-1)(3.4)^{2}+(9-1)(3.6)^{2}}{11+9-2} = 12.1822$

The 99% confidence interval for the true mean difference between the mean drying time of type A and the mean drying time of type B is given by

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{11}+\frac{1}{9}}$ , i.e.,

$(71.5-68.5)\pm t_{0.005}(3.4903)\sqrt{\frac{1}{11}+\frac{1}{9}}$

where $t_{0.005}$ is the 0.5th quantile of the t distribution with (11+9-2) = 18 degrees of freedom. So

$3\pm(-2.8784)(3.4903)(0.4495)$ , i.e.,

the indicated confidence interval for the difference between the two population means is (-1.5159, 7.5159)

5 0

3 years ago

A water pump is filling up a tank in the shape of an inverted cone. The top of the cone has a diameter of 12 meters, and the con

olga_2 [115]

Answer:

20/(9π) m/min ≈ 0.707 m/min

Step-by-step explanation:

The rate of change of height is the rate of change of volume divided by the surface area. Of course, the surface area is given by πr², where r = d/2 = 3 m.

dh/dt = (dV/dt)/A = (20 m³/min)/(π(3 m²))

dh/dt = 20/(9π) m/min ≈ 0.707 m/min

5 0

3 years ago