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3 years ago

What is the problem for this Problem?

Mathematics

1 answer:

ratelena [41]3 years ago

7 0

Answer:

Negative: (-∞,-3] and [1/2,-∞)

Positive: [-3,1/2]

Step-by-step explanation:

The derivative is the instantaneous rate of change at any given point for a function. Given this we know that anywhere the function is in the positive or negative direction, the derivative will also be in the positive or negative direction. We also know that wherever there is a peak or a trough, there will be no slope and it signifies a change in direction. For this function, this means the direction changes at -3 and 1/2.

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Carry out the following operation as if it were a calculation of real experimental results. Express the answer in the correct un

Vladimir79 [104]

Answer:

a) 1.28

b) 2.57*10^-7 mg²

c) 8.14*10^7 dm

d) 3.79 m/s

e) 9.78*10^-3 mg

Step-by-step explanation:

a) 7.31 / 5.7 = 1.28, km/km is the same unit, so they cancel each other out. The answer is 1.28 without unit.

b) (3.26*10^-3) * (7.88*10^-5) = 2.57*10^-7 mg², here, mg * mg, this is mg²

c) (4.02*10^6) + (7.74*10^7) = 8.14*10^7 dm, here, the unit are added together, so we maintain it

d) (7.8 - 0.34) m / (1.15 + 0.82) m = 7.46 m / 1.97 m = 3.79 m/s, here, the numerator has the unit of m, and the denominator has the unit of s. Giving us m/s.

e) (9.88*10^-3) - (9.66*10^-5) = 9.78*10^-3 mg. Here, the unit was subtracted from each other, so we maintain it.

7 0

3 years ago

9y-36=-15x in Slope intercept form

vodka [1.7K]

Look in the file below

6 0

4 years ago

Read 2 more answers

PLEASE HELP! I JUST NEED SOMEONE TO GRAPH MY ANSWER! I HAVE THE ANSWER, JUST NEED THE GRAPH!

Juli2301 [7.4K]

Let
e = Gibson Explorer’s = 20
v = Gibson Flying V’s

So, our problem is

Maximize
Money = 80e + 5v

Subject to
0 ≤ e ≤ 20
0 ≤ v ≤ 20
0 ≤ e + v ≤ 30

In order to solve this problem, we look at the graph (attached), and find the value of Money =80e + 5v at corner points to find the maximum value of money.

(e,v)=(0,0) >> Money = 80e+5v = 80*0+5*0 = 0
(e,v)=(0,20) >> Money = 80e+5v = 80*0+5*20 = 100
(e,v)=(20,0) >> Money = 80e+5v = 80*20+5*0 = 1600
(e,v)=(20,10) >> Money = 80e+5v = 80*20+5*10 = 1650 (maximum)
(e,v)=(10,20) >> Money = 80e+5v = 80*10+5*20 = 900

So Bob can make the most money = $1,650 when he makes and sell
e = Gibson Explorer’s = 20
v = Gibson Flying V’s = 10

4 0

4 years ago

Find tan , sin , and seco, where 0 is the angle shown in the figure.

kicyunya [14]

Answer:

tan(θ) = 5/3
sin(θ) = 5√34/34
sec(θ) = √34/3

Step-by-step explanation:

The hypotenuse is given by the Pythagorean theorem:

h = √(3² +5²) = √34

The trig functions are the ratios of sides:

Tan = Opposite/Adjacent

tan(θ) = 5/3

Sin = Opposite/Hypotenuse

sin(θ) = 5/√34 = (5/34)√34

Sec = Hypotenuse/Adjacent

sec(θ) = √34/3

3 0

3 years ago

The graphs of g(x) has only one x-intercept and is an odd function. The points (0,0), (1,3), and (3,1) are on the graphs of g(x)

Eddi Din [679]

Using translation concepts, it is found that the new intercepts are given as follows:

x-intercept: (1, 0).

y-intercept: (0, -3).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

In this problem, the function was shifted one unit right, hence the rule for the translated function is given by:

(x,y) -> (x + 1, y).

The y-intercept is given by f(0), hence for the shifted function it will be f(-1). We have that f(x) is an odd function and f(1) = 3, hence f(-1) = -f(1) = -3.

The x-intercept is given by x when f(x) = 0, hence:

(0,0) -> (0 + 1, 0) = (1,0).

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

6 0

1 year ago