Question

Help please Is this correct?, I don't know if I did this right.

Answer 1

Answer:

your image is not clear. I maybe that's your right answer

Answer 2

Answer: Infinitely many solutions

Any real number works for x

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Work Shown:

$6 - 2x - 1 = 4x+5 - 6x\\\\-2x+6 - 1 = 4x - 6x+5\\\\-2x+5 = -2x+5$

We get the same identical expression on both sides. So plugging any number in for x leads to getting the same number on both sides.

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For instance, if x = 0,

$-2x+5 = -2x+5\\\\-2(0)+5 = -2(0)+5\\\\5 = 5$

which is a true statement. The same happens when we plug x = 0 into the original equation

$6 - 2x - 1 = 4x+5 - 6x\\\\6 - 2(0) - 1 = 4(0)+5 - 6(0)\\\\6 - 0 - 1 = 0+5 - 0\\\\5 = 5$