Find the amplitude of the function. y=1/5 sin 4x

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

6 0

Answer:

option b

1.5

Step-by-step explanation:

Given in the question an equation,

y = 1.5sin4x

The amplitude of y=asin(x) represents half the distance between the maximum and minimum values of the function.

Amplitude = |a|

In the equation y = 1.5sin4x, a = 1.5

So, amplitude of graph y = 1.5sin4x = 1.5

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Step-by-step explanation:

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Let ABC be an isosceles triangle with AB = AC and ∠BAC=30°. Side AB and the median AD contain points Q and P respectively (point

Svet_ta [14]

Answer:

15°

Step-by-step explanation:

Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)

The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.

Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.

Angle PQC is 15°.