120,808.8
Not sure if this is right, comment if it’s not
To solve for this, we need to find for the value of x
when the 1st derivative of the equation is equal to zero (or at the
extrema point).
So what we have to do first is to derive the given
equation:
f (x) = x^2 + 4 x – 31
Taking the first derivative f’ (x):
f’ (x) = 2 x + 4
Setting f’ (x) = 0 and find for x:
2 x + 4 = 0
x = - 2
Therefore the value of a is:
a = f (-2)
a = (-2)^2 + 4 (-2) – 31
a = 4 – 8 – 31
a = - 35
Answer: G
Step-by-step explanation:
Answer: there are no solutions
Step by step: Step 1: Simplify both sides of the equation.
3
(
x
−
1
)
=
5
x
+
3
−
2
x
(
3
)
(
x
)
+
(
3
)
(
−
1
)
=
5
x
+
3
+
−
2
x
(Distribute)
3
x
+
−
3
=
5
x
+
3
+
−
2
x
3
x
−
3
=
(
5
x
+
−
2
x
)
+
(
3
)
(Combine Like Terms)
3
x
−
3
=
3
x
+
3
3
x
−
3
=
3
x
+
3
Step 2: Subtract 3x from both sides.
3
x
−
3
−
3
x
=
3
x
+
3
−
3
x
−
3
=
3
Step 3: Add 3 to both sides.
−
3
+
3
=
3
+
3
0
=
6
