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3 years ago

LMNO~QRST find the value of x.

Mathematics

1 answer:

adelina 88 [10]3 years ago

4 0

Since both trapezoids are similar, so LMNO is a scaled version of QRST by some magnitude
so we can easily use the concept of ratios to find x
in other words: x÷2=6÷5
so x=6×2÷5=12/5=2.4
x=2.4

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Please help me <br>find f(x+h)

Kay [80]

Answer:

f(x) = -2x+5

f(x+h) = -2x -2h +5

g(x) = -4x-2

g(x+h) = -4x -4h -2

h(x) = 4x^2+1

h(x+h) = 4(x+h)^2 +1 = 4x^2 +8xh + 4h^2 +1

Q(x) = -3x^2 +4

Q(x+h) = -3(x+h)^2 +4 = -3x^2 -3h^2 -6xh + 4

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2 years ago

Find the requested information based on the given facts. Base: $54,300: Total Sales: $950,000; Commission: 2.75% Determine the t

Dafna11 [192]

Answer:

$871068.25

Step-by-step explanation:

Given the base of starting the business is $54300 and the total sale after the business is $950000.

Therefore, the profit of the business is $(950000-54300) = $895700.

Now, the commission has to be deducted from the profit at the rate of 2.75% of the profit.

Hence, total profit of the business is given by

895700 [1 - $\frac{2.75}{100}$ ] = $871068.25 (Answer)

6 0

3 years ago

A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w

sveta [45]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for business

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for Business

$n_A=400$ is the sample size required for Business

$p_B$ represent the real population proportion for non Business

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non Business

$n_B=500$ is the sample size required for non Business

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

7 0

3 years ago

Triangle ABC is translated according to the rule (x,y) arrow (x+2,y-8) if the coordinates of the pre image of point B are (4,-5)

kherson [118]

Answer: the coordinates of B' are (6, -13)

Justification:

1) Translating triangle ABC according to the rule (x,y) → (x + 2, y - 8) means that every single point of the triangle will be translated two units to the righ (x + 2) and 8 units downward (y - 8).

2) To find the coordinates of anay image you have to add up 2 to the x coordinate (x + 2) and subtract 8 from the y-coordinate (y - 8).

3) Peforming those simple operations to the coordinates of the point B (4, -5), you will obtain the point B':

* x' = x + 2 = 4 + 2 = 6
* y' = y - 8 = -5 - 8 = - 13

Answer: the coordinates of B' are (6, -13)

5 0

3 years ago

Math problem easy! Giving 40 points and brainly!!

alexandr1967 [171]

Answer B the second one

5 0

3 years ago