Y = 2x + 1
y = x²+1
reemplazando
2x+1 = x²+1
ordenando
0=x²-2x
donde
0 = x (x-2)
resolviendo
0=x v x-2=0
0 =x x= 2
si x=0 entonces y = 1 par (0,1)
si x=2 entonces y= 5 par (2,5)
respuesta A
12.78 because if you do ( 12 X .065 you get .78 which you then add to 12$ and get a total of 12.78
Answer:
The payment would be $ 897.32.
Step-by-step explanation:
Since, the monthly payment of a loan is,
Where, PV is the present value of the loan,
r is the monthly rate,
n is the total number of months,
Here,
PV = $170,000,
Annual rate = 4 % = 0.04
So, the monthly rate, r = 
( 1 year = 12 months )
Time in years = 25,
So, the number of months, n = 12 × 25 = 300
Hence, the monthly payment of the debt would be,
Answer:
Therefore r'(t) =-k sin t i + k cos t j and |r'(t)| = k so T(t) = r'(t)/|r'(t)| = -sin t i + cos t j and T'(t) = -cos t i- sin t j . This gives |T'(t)| = 1, so using this equation, we have κ(t) = |T'(t)|/|r'(t)| = 1/k.
Step-by-step explanation:
We are already given the definition of curvature and the parametrization needed to find the curvature of the circle. In genecral the curvature κ is equal to κ(t)=|T'(t)|/|r'(t)| where r(t) is a parametrization of the curve and T(t) is the normalized tangent vector respect to the parametrization, that is, T(t)=r'(t)/|r'(t)|.
Now, using the derivatives of sines and cosines, and the definition of norm, we obtain that:
r(t) = k cos t i + k sin t j ⇒ r'(t)=-k sin t i + k cos t j ⇒|r'(t)|²=sin²t+cos²t=1
T(t) = r'(t)/|r'(t)|=-sin t i +cos t j ⇒ T'(t)= -cos t i - sin t j ⇒|T'(t)|²=cos²t+sin²t=1
Answer:
x = 4
Step-by-step explanation:
