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Alja [10]
3 years ago
9

A car travels down a highway at a constant speed shown in the graph below.

Mathematics
2 answers:
LenKa [72]3 years ago
5 0

Answer:

80 per hour

Step-by-step explanation:

because every hour it goes up 80 every time

lana [24]3 years ago
4 0

Answer:it’s 80

Step-by-step explanation:

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I'm supposed to simplify this.
tekilochka [14]

Answer:

C

Step-by-step explanation:

the proof of the answer is seen in the diagram

4 0
3 years ago
Ben is a tour guide at museum. each tour group can have no more than 7 people/ If Ben give tours to 66 people . How many tours w
Nataly [62]
10 because 7x9 which is the closest you can get to 66 is 7x9 which is 63 and those 3 extra people need a tour too so thats another one
7 0
3 years ago
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PLEASE HELP FAST!!!!!!!!!!!!!!!!!!!!!!!!!!!ASAP
AveGali [126]

Answer:

x=2.50

Step-by-step explanation:

But I am not sure if its positive or negative.

6 0
3 years ago
Find the limit, if it exists, or type dne if it does not exist.
Phantasy [73]
\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}

Suppose we choose a path along the x-axis, so that y=0:

\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1

On the other hand, let's consider an arbitrary line through the origin, y=kx:

\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}

The value of the limit then depends on k, which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.
8 0
4 years ago
What is the justification for step 2 in the solution process?
Maksim231197 [3]

Answer:

Subtract property of deviation becasue your subtracting 6y frrom both sides of the equation.

Step-by-step explanation:

1)Given: 12y - 40 - 4y = 6y - 18

2)Simplify by adding 12y + (-4y): 8y - 40 = 6y - 18

3)Subtract property of deviation: 8y -6y - 40 = 6y -6y - 18

2y - 40 = -18

<em>Hope this helped!</em>

8 0
3 years ago
Read 2 more answers
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