The answer is true because I don't know
Answer:
Question is incomplete.
Assuming the below info to complete the question
You have a collection of n lockboxes and m gold keys. Each key unlocks at most one box. Without a matching key, the only way to open a box is to smash it with a hammer. Your baby brother has locked all your keys inside the boxes! Luckily, you know which keys (if any) are inside each box.
Detailed answer is written in explanation field.
Explanation:
We have to find the reachability using the directed graph G = (V, E)
In this V are boxes are considered to be non empty and it may contain key.
Edges E will have keys .
G will have directed edge b1b2 if in-case box b1 will have key to box b2 and box b1 contains one key in it.
Suppose if a key opens empty box or doesn’t contain useful key means can’t open anything , then it doesn’t belongs to any edge.
Now, If baby brother has chosen box B, then we have to estimate for other boxes reachability from B in Graph G.
If and only if all other boxes have directed path from box B then just by smashing box B we can get the key to box b1 till last box and we can unlock those.
After first search from B we can start marking all other vertex of graph G.
So algorithm will be O ( V +E ) = O (n+m) time.
I believe the answer is bloody purple poop that is the size of an extra large grilled cheese
The indices of the internal array elements that hold the remaining elements is c) 2 to 4
<h3>Calculations and Parameters:</h3>
For us to create a capacity of 10 for the queue, we would enqueue:
We would create a queue of capacity 10:
<h3>Queue q(10);</h3>
We add elements/enqueue 5 elements to the queue :
- q.queueEnqueue(10);
- q.queueEnqueue(5);
- q.queueEnqueue(8);
- q.queueEnqueue(9);
- q.queueEnqueue(2);
Printing this would give:
q. queueDisplay()
10, 5, 8, 9, 2
Next, we would remove elements/dequeue 2 elements from the queue :
q. queuedequeue();
q. queuedequeue();
Printing it would be:
q. queueDisplay()
8 ,9, 2
Observing this, the deletion/dequeue starts from the front/first index.
The remaining indices of the internal array elements are: 2, 3, 4 or 2 to 4
Read more about arrays and enqueue here:
brainly.com/question/24188935
#SPJ1
