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irga5000 [103]
3 years ago
11

X^2/16 + y^2/25 = 1 The major axis runs along the: x-axis y-axis line y=x

Mathematics
1 answer:
Nuetrik [128]3 years ago
3 0

Answer:

y-axis

Step-by-step explanation:

We have the equation:

\frac{ {x}^{2} }{16}  +  \frac{ {y}^{2} }{25}  = 1

This is the equation of an ellipse with vertex at origin.

We can rewrite this equation as:

\frac{ {x}^{2} }{ {4}^{2} }  +  \frac{ {y}^{2} }{ {5}^{2} }  = 1

Comparing this to

\frac{ {x}^{2} }{ {b}^{2} }  +  \frac{ {y}^{2} }{ {a}^{2} }  = 1

We a=5 and b=4

Since a>b, the major axis runs along the y-axis

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Write the equation of the line given the slope and point that it passes through
Harman [31]

Answer:

Assuming you want the answer in slope-intercept form, it’s <u>y = -5x + 11</u>

Step-by-step explanation:

So we have to first use point-slope form, y - y1 = m (x - x1)

If we plug the numbers in we get...

y + 4 = -5 (x - 3) (take out parenthesis)

y + 4 = -5x + 15 (now subtract 4 from 15)

<u>y = -5x + 11</u>

I think this is right

4 0
3 years ago
CAN SOMEONE CHECK MY ANSWER
tigry1 [53]

Answer:

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Given sin y = -4/5, where π &lt; y &lt; 3π/2, and cos x = 12/13, where 0 &lt; x &lt; π/2. Find the exact value of sin (x - y).
konstantin123 [22]

Answer:

Solution given:

sin y = -4/5

p/h=4/5

p=4

h=5

b=√{5²-4²)=3

cos y = b/h=-3/5

again

cos x=12/13

b/h=12/13

b=12

h=13

p=√(13²-12²)=5

sin x=p/h=5/13

now

sin[x-y]=sinxcosy-cosxsiny

=5/13×-3/5-(12/13×-4/5)=33/65 is your answer.

3 0
3 years ago
A student paid at least 51$ for a computer diskette. The total charge includes the price and 2% tax. Find minimum price of the d
BartSMP [9]
52.02 at is the minimum 
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3 years ago
Point B is 2/3 the way from A(-2,5)to C(4,-4). Find the location of B
mr Goodwill [35]

well, we'll first off put the point AC in component form by simply doing a subtraction of C - A, multiply that by the fraction 2/3, and that result will get added to point A, to get point B.

\bf \textit{internal division of a segment using a fraction}\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-4})~\hfill \frac{2}{3}\textit{ of the way from }A\to C \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_2}{4}-\stackrel{x_1}{(-2)}, \stackrel{y_2}{-4}-\stackrel{y_1}{5})\implies (4+2,-9) \stackrel{\textit{component form of segment AC}}{\qquad \implies \qquad (6,-9)} \\\\[-0.35em] ~\dotfill

\bf \stackrel{~\hfill \textit{coordinates to be added to point A}} {\cfrac{2}{3}(6,-9)\implies \cfrac{2}{3}(6)~,~\cfrac{2}{3}(-9)\qquad \implies \qquad \left(4,-6\right)} \\\\\\ \stackrel{\textit{additions to point A}} {\stackrel{\textit{point A}}{(-2,5)}+\left( 4,-6\right)}\implies \left( -2+4~~,~~5-6\right) = B\implies (2~,~-1)=B

5 0
3 years ago
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