The answer to this question is 3
Answer:
t ≤ 4x + 10
Step-by-step explanation:
The amount of money that Josh spends on rides is the variable T, found in the problem. Josh wants to spend AT MOST t. That means he can spend as little as he wants, but he can't ride too many times so that the cost goes over T. Therefore, it has to be less than. But, it can also be equal to, as he can ride exactly many rides up to T, it just can't go over it.
Next, the cost to get into the fair is ten dollars, meaning if he goes on only one ride, that will cost him 4 dollars, but actually will have cost him 14 dollars because of the entrance fee. So, no matter how many rides he goes on, there is always the entrance fee added on.
Finally, the cost for each ride is 4 dollars per ride or 4 times x with x being the number of rides he goes on.
So, for our answer, we have t ≤ 4x + 10!
Answer:
f(x) = 3
+ 2
Step-by-step explanation:
Given G(x) =
As we can see, the graph of f(x) is 2 units above the graphof g(x) in vertical (vertical shift)
=> f(x) = a + 2
As you can see, the graph of f(x) is stretched vertically by a dilation factor of 3
and there is no reflection, so a= 3
=> the equation of f(x) is: f(x) = 3 + 2
Answer:
12.42 = 1242 / 100;
4.6 = 46 / 10;
12.42 ÷ 4.6 = (1242 / 100) ÷ (46 / 10 ) = (1242 / 100) x (10 / 46 ) = ( 1242 / 46 ) x ( 100 / 10 ) = 27 x 10 = 270;
Step-by-step explanation:
