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antoniya [11.8K]
3 years ago
13

Find the area of the trapezoid

Mathematics
2 answers:
katovenus [111]3 years ago
4 0

Answer: 49 in^2

Step-by-step explanation:

Trapezoid area formula = (a+b/2) x h

So...

(5+9/2) x 7

= 49 in^2

hammer [34]3 years ago
3 0

\huge \boxed {\longmapsto\mathcal {\purple {Answer}}}

Area of trapezoid :

\boxed{ \frac{1}{2} \times sum \: of \: parallel \: sides \times height }

=》

\boxed  {\frac{1}{2}  \times (9 + 5) \times 7}

=》

\boxed  {\frac{1}{2}  \times 14 \times 7}

=》

\boxed{7 \times 7}

=》

\boxed{49}

\boxed {\mathfrak{area  = 49 \:in {}^{2} }}

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Step-by-step explanation:

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Read 2 more answers
1. A drawing of a triangular park shows that the sides measure 12 m, 30 m, and 18 m. Can these dimensions be correct?
Varvara68 [4.7K]

Answer: 1. It is not possible to construct a triangle of given measure sides.

2. The value of ∠A is 44°

Step-by-step explanation:

1.

Given: Three sides of a triangle

Let a= 12 m , b=30 m and c= 18 m

Now as we know

The sum of two sides of a triangle is always greater than the third side

Therefore we need to show

a+b>c -----(i)

b+c>a -----(ii)

c+a>b -----(iii)

(i a+b= 12+30 = 42>18= b ⇒ a+b>c

ii) b+c=30+18= 48 >12=a ⇒ b+c>a

iii) c+a=18+12=30=b ⇒ c+a= b

Therefore the third condition does not verified

Hence, it is not possible to construct a triangle of given measure sides.

2.

As we now triangle sum property which states that the sum of all the three angles of a triangle is 180°

So we have

x+59+84+x+51=180\\\\\Rightarrow 194 +2x=180\\\\\Rightarrow 2x= 180-194\\\\\Rightarrow 2x=-14\\\\\Rightarrow x= -7

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