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2 years ago

Find the area of the trapezoid

Mathematics

2 answers:

katovenus [111]2 years ago

4 0

Answer: 49 in^2

Step-by-step explanation:

Trapezoid area formula = (a+b/2) x h

So...

(5+9/2) x 7

= 49 in^2

hammer [34]2 years ago

3 0

$\huge \boxed {\longmapsto\mathcal {\purple {Answer}}}$

Area of trapezoid :

$\boxed{ \frac{1}{2} \times sum \: of \: parallel \: sides \times height }$

=》

$\boxed {\frac{1}{2} \times (9 + 5) \times 7}$

=》

$\boxed {\frac{1}{2} \times 14 \times 7}$

=》

$\boxed{7 \times 7}$

=》

$\boxed{49}$

$\boxed {\mathfrak{area = 49 \:in {}^{2} }}$

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3 years ago

Read 2 more answers

PLEASE HELP For the expression below, write two other equivalent expressions using different terms. Make sure one is fully simpl

Julli [10]

Given:

The given expression is

$-4(x+2)-2x+4$

To find:

The two other equivalent expressions.

Solution:

We have,

$-4(x+2)-2x+4$

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5 0

3 years ago

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a

Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = $\sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}$

= ${^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}$ + .......+ ${^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}$

= 0.04541 + ......+0.0000002079

= 0.1076

⇒Probability that at least 490 do not result in birth defects = 0.1076

4 0

3 years ago