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antoniya [11.8K]
2 years ago
13

Find the area of the trapezoid

Mathematics
2 answers:
katovenus [111]2 years ago
4 0

Answer: 49 in^2

Step-by-step explanation:

Trapezoid area formula = (a+b/2) x h

So...

(5+9/2) x 7

= 49 in^2

hammer [34]2 years ago
3 0

\huge \boxed {\longmapsto\mathcal {\purple {Answer}}}

Area of trapezoid :

\boxed{ \frac{1}{2} \times sum \: of \: parallel \: sides \times height }

=》

\boxed  {\frac{1}{2}  \times (9 + 5) \times 7}

=》

\boxed  {\frac{1}{2}  \times 14 \times 7}

=》

\boxed{7 \times 7}

=》

\boxed{49}

\boxed {\mathfrak{area  = 49 \:in {}^{2} }}

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What is the equation of a line with slope −23 and a y-intercept of −4 ?
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Answer:

its A

Step-by-step explanation:

the y intercept would be -4 and the slope would be -23, put it in y=mx+b form

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System A:x=3y=-9 2x=y=4 system B: 3x+4y=-9 2x+y=4 how can we get system b from system A? Are the systems Equivalent? TEST NEED H
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3 0
3 years ago
Read 2 more answers
PLEASE HELP For the expression below, write two other equivalent expressions using different terms. Make sure one is fully simpl
Julli [10]

Given:

The given expression is

-4(x+2)-2x+4

To find:

The two other equivalent expressions.

Solution:

We have,

-4(x+2)-2x+4

Using distributive property, we get

=-4(x)-4(2)-2x+4

=-4x-8-2x+4

So, one equivalent expression is -4x-8-2x+4.

On further simplification, we get

=(-4x-2x)+(-8+4)

=6x-4

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5 0
3 years ago
The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a
Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = \sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}

                 = {^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}  + .......+ {^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}

                = 0.04541 + ......+0.0000002079

                = 0.1076

⇒Probability that at least 490 do not result in birth defects = 0.1076

4 0
3 years ago
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