Answer:
Can you Specify the Question?
x = the number of miles
y = the total cost
Company A:
0.60x + 60 = y [Company A charges $60 plus $0.60 per mile(x)]
Company B:
0.90x + 30 = y [Company B charges $30 plus $0.90 per mile(x)]
To find the number of miles where the costs for both companies are the same, you can set the equations equal to each other as the costs(y) are the same:
y = y Substitute the equations into "y" (substitute (0.60x + 60) and (0.90x + 30) into "y" since y = 0.60x + 60 and y = 0.90x + 30)
0.60x + 60 = 0.90x + 30 To find x, isolate/get the variable "x" by itself. Subtract 30 on both sides
0.60x + 60 - 30 = 0.90x + 30 - 30
0.60x + 30 = 0.90x Subtract 0.60x on both sides to get "x" on one side of the equation
0.60x - 0.60x + 30 = 0.90x - 0.60x
30 = 0.30x Divide 0.30 on both sides to get "x" by itself
100 = x 100 miles
(if you need to find out the cost where both companies cost the same, you can substitute/plug in the value of x into one of the equations.)
0.60x + 60 = y Plug in 100 into "x" since x = 100
0.60(100) + 60 = y
120 = y At 100 miles, both companies cost $120
Answer:
A. Brandon can swim 0.375 laps every minute and Peter can swim 0.4 laps a minute.
B. Brandon 0.375 laps a minute Peter 0.4 laps a minute
C. Peter will swim 20 laps first I know because the rate at which he swims is faster than Brandon's
D would be more logic because the total of kids playing football and hour everyday and he would be able to count for in a whole week
Answer:
13/30
Step-by-step:
First, you find the common denominator, which is 30. For the first fraction, multiply the bottom by five. Since you do that, you have to multiple the top by 5 as well, giving you 25/30. For the second problem, you multiple the top and bottom by six giving you 12/30. 25 minus 12 is 13 so you get 13/30.
