Answer:
Coefficient is your answer
Answer: 12
Step-by-step explanation:
Given the question :
Given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer?
The number of different positive two integer number can be obtained by:
P(4, 2) = 4P2
Recall:
nPr = n! / (n - r)!
4P2 = 4! / (4 - 2)!
4P2 = 4! / 2!
4P2 = (4 * 3 * 2 * 1) / ( 2 * 1)
4P2 = 24 / 2
4P2 = 12
Hence, 12 different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer
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Answer: A. (4,1)
Step-by-step explanation:
2x -5y = 3
x -3y = 1
Change the equation to isolate a variable so you can substitute it in the other one.
x = 1+3y so
2(1+3y) -5y = 3
2 + 6y -5y =3
2 + y = 3
y=1
Back to the easy equation we isolated
x = 1+3(1)
x= 4
(4,1) is a point where x=4 and y=1
Answer:
B: 20% of students surveyed have a hamster
Step-by-step explanation:
Hopefully this helps!
