Question

What are the lengths of the legs of a right triangle in which one acute angle measures 19o and the hypotenuse is 15 units long?

Answer 1

$x,y-\ lengths\ of\ legs\\\\sin19^\circ=\frac{x}{15}\\\\ sin19^\circ*15=x\\\\0,32*15=x\\\\x=4,8\\\\ y^2+(4,8)^2=15^2\\\\y^2=225-23,04\\\\ y^2=201,96\\\\y=14,2\\\\Legs\ are\ equalt\ to:\ 4,8 \ and\ 14,2.$