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3 years ago

Hey guys!! U think u can help me? Plss :))

Mathematics

2 answers:

alexgriva [62]3 years ago

6 0

Answer:

The false statement is 'The plant grows 1 centimeter every day'.

Step-by-step explanation:

As it is shown on the graph, the plant only grows 0.1 centimeters a day.

The plant grows a centimeter every 10 days, so the statement is false.

slavikrds [6]3 years ago

3 0

Answer:

A: The plant grows 1CM every day

Step-by-step explanation:

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Please answer this question!! 30 points and brainliest!

Zepler [3.9K]

B. 1/4 that should be the answer

4 0

4 years ago

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Thursday, Jamal made y dollars per hour for 9 hours of

denis23 [38]

Answer:

The expression for the total amount of Jamal earned is $ (14 y + 55)

Step-by-step explanation:

Given as :

The bonus amount earn by Jamal = $ 55

According to question

On Thursday

∵ For 1 hour of work , Jamal earn y dollars

∴ For 9 hours of work , Jamal will earn 9 × y = 9 y dollars

On Friday

∵ For 1 hour of work , Jamal earn y dollars

∴ For 5 hours of work , Jamal will earn 5 × y = 5 y dollars

So, The total earning on both days of his work = 9 y + 5 y = 14 y dollars

Since Jamal also earn bonus of $ 55

So, Total earning of Jamal including bonus = 14 y + $ 55

Hence The expression for the total amount of Jamal earned is $ (14 y + 55) Answer

6 0

3 years ago

Marci needs to rent a storage unit.

11111nata11111 [884]

Message me directly so I can solve this, give me a thank you plz

3 0

3 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago

A ball is projected upward at time t = 0.0 s from a point on a roof 90 m above the ground. The ball rises, then falls and strike

kykrilka [37]

UPWARD JOURNEY
(g is -ive)
u= 80.5m/s
Height reached= u^2/2g= 324m

Height of the ball at topmost point of journey= 414m

DOWNWARD JOURNEY
(g is +ive)
u=0
We need to find the velocity at 89m from ground, which is equivalent to finding velocity at 325 m from the topmost point in downward direction.

v= √2gh= √2*10*325= 80.6= 81 m/sec(Answer)

5 0

3 years ago

Read 2 more answers